The one that is not an option of the 3 technology bets made are Digital core and Design Thinking.
<h3>What are the 3 technology bets Genpact produced?</h3>
The digital technologies made are known to be able to create value through the accelerating processes and also by automating them.
The technology bets Genpact are:
- Artificial Intelligence.
- Augmented Intelligence.
- Customer Experience.
- Digital Transformation and AI Consulting.
- Intelligent Automation.
Learn more about technology from
brainly.com/question/25110079
Answer:
The angle between the earth and the sun as seen from a planet is called phase angle.
Answer:
Both Techs A and B
Explanation:
Electronic braking systems are controlled by the electronic brake control module. It is a microprocessor that processes information from wheel-speed sensors and the hydraulic brake system to determine when to release braking pressure at a wheel that's about to lock up and start skidding and activates the anti lock braking system or traction system when it detects it is necessary.
Some electronic brake control modules can be programmed to the size of the vehicle's new tires to restore proper electronic brake control performance. While others may require replacing the module to match the module's programming to the installed tire size. So, both technicians A and B are correct.
Answer:
Activation energy for creep in this temperature range is Q = 252.2 kJ/mol
Explanation:
To calculate the creep rate at a particular temperature
creep rate, ![\zeta_{\theta} = C \exp(\frac{-Q}{R \theta} )](https://tex.z-dn.net/?f=%5Czeta_%7B%5Ctheta%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%5Ctheta%7D%20%29)
Creep rate at 800⁰C, ![\zeta_{800} = C \exp(\frac{-Q}{R (800+273)} )](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%28800%2B273%29%7D%20%29)
![\zeta_{800} = C \exp(\frac{-Q}{1073R} )\\\zeta_{800} = 1 \% per hour =0.01\\](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7B1073R%7D%20%29%5C%5C%5Czeta_%7B800%7D%20%3D%201%20%5C%25%20per%20hour%20%3D0.01%5C%5C)
.........................(1)
Creep rate at 700⁰C
![\zeta_{700} = C \exp(\frac{-Q}{R (700+273)} )](https://tex.z-dn.net/?f=%5Czeta_%7B700%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7BR%20%28700%2B273%29%7D%20%29)
![\zeta_{800} = C \exp(\frac{-Q}{973R} )\\\zeta_{800} = 5.5 * 10^{-2} \% per hour =5.5 * 10^{-4}](https://tex.z-dn.net/?f=%5Czeta_%7B800%7D%20%3D%20C%20%5Cexp%28%5Cfrac%7B-Q%7D%7B973R%7D%20%29%5C%5C%5Czeta_%7B800%7D%20%3D%205.5%20%2A%2010%5E%7B-2%7D%20%20%5C%25%20per%20hour%20%3D5.5%20%2A%2010%5E%7B-4%7D)
.................(2)
Divide equation (1) by equation (2)
![\frac{0.01}{5.5 * 10^{-4} } = \exp[\frac{-Q}{1073R} -\frac{-Q}{973R} ]\\18.182= \exp[\frac{-Q}{1073R} +\frac{Q}{973R} ]\\R = 8.314\\18.182= \exp[\frac{-Q}{1073*8.314} +\frac{Q}{973*8.314} ]\\18.182= \exp[0.0000115 Q]\\](https://tex.z-dn.net/?f=%5Cfrac%7B0.01%7D%7B5.5%20%2A%2010%5E%7B-4%7D%20%7D%20%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073R%7D%20-%5Cfrac%7B-Q%7D%7B973R%7D%20%5D%5C%5C18.182%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073R%7D%20%2B%5Cfrac%7BQ%7D%7B973R%7D%20%5D%5C%5CR%20%3D%208.314%5C%5C18.182%3D%20%5Cexp%5B%5Cfrac%7B-Q%7D%7B1073%2A8.314%7D%20%2B%5Cfrac%7BQ%7D%7B973%2A8.314%7D%20%5D%5C%5C18.182%3D%20%5Cexp%5B0.0000115%20Q%5D%5C%5C)
Take the natural log of both sides
![ln 18.182= 0.0000115Q\\2.9004 = 0.0000115Q\\Q = 2.9004/0.0000115\\Q = 252211.49 J/mol\\Q = 252.2 kJ/mol](https://tex.z-dn.net/?f=ln%2018.182%3D%200.0000115Q%5C%5C2.9004%20%3D%200.0000115Q%5C%5CQ%20%3D%202.9004%2F0.0000115%5C%5CQ%20%3D%20252211.49%20J%2Fmol%5C%5CQ%20%3D%20252.2%20kJ%2Fmol)
Answer:
c = 18.0569 mm
Explanation:
Strategy
We will find required diameter based on angle of twist and based on shearing stress. The larger value will govern.
Given Data
Applied Torque
T = 750 N.m
Length of shaft
L = 1.2 m
Modulus of Rigidity
G = 77.2 GPa
Allowable Stress
г = 90 MPa
Maximum Angle of twist
∅=4°
∅=4*
/180
∅=69.813 *10^-3 rad
Required Diameter based on angle of twist
∅=TL/GJ
∅=TL/G*
/2*c^4
∅=2TL/G*
*c^4
c=
∅
c=18.0869 *10^-3 rad
Required Diameter based on shearing stress
г = T/J*c
г = [T/(J*
/2*c^4)]*c
г =[2T/(J*
*c^4)]*c
c=17.441*10^-3 rad
Minimum Radius Required
We will use larger of the two values
c= 18.0569 x 10^-3 m
c = 18.0569 mm