Answer:
You can better relate to the air temperature.
Explanation:
Fahrenheit gives you almost double the precision of Celsius without having to use decimals.
Answer:
Option C. 52.057
Explanation:
The following data were obtained from the question:
Isotope >> Mass number > Percentage
A (Cr-50) > 50 >>>>>>>>>> 4.3
B (Cr-52) > 52 >>>>>>>>>> 83.8
C (Cr-53) > 53 >>>>>>>>>> 9.5
D (Cr-54) > 54 >>>>>>>>>> 2.4
Average atomic mass =?
The average atomic mass of chromium, Cr can be obtained as follow:
Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]
Atomic mass of Cr = [50×4.3)/100] + [52×83.8)/100] + [53×9.5)/100] + [54×2.4)/100]
= 2.15 + 43.576 + 5.035 + 1.296
Atomic mass of Cr = 52.057
Therefore, the atomic mass of chromium, Cr is 52.057
Answer:
1.3M
Explanation:
Convert from grams to moles:
molar mass of HCl = 1.01g(molar mass of H) + 35.45g(molar mass of Cl) = 36.46g HCl
1.2g HCl (1mol HCl/36.46g HCl)
= .0329 mol HCl
Molarity = mol/L (important formula for concentration)
Plug your values in:
Molarity = .0329mol/.025L
1.317M - but you used two significant figures in the question, so:
1.3M
Answer: Option (d) is the correct answer.
Explanation:
Electronegativity value of hydrogen is 2.2.
Electronegativity value of chlorine is 3.16.
Electronegativity value of carbon is 2.55.
Electronegativity value of oxygen is 3.44.
Electronegativity value of nitrogen is 3.04.
Electronegativity value of sodium is 0.93.
Electronegativity value of iodine is 2.66.
Therefore, calculate the electronegativity difference between the bonded atoms as follows.
- Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen
= 3.16 - 2.2
= 0.96
- Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon
= 3.44 - 2.55
= 0.89
- Electronegativity difference of
= Electronegativity value of nitrogen - electronegativity value of nitrogen
= 3.04 - 3.04
= 0
- Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium
= 2.66 - 0.93
= 1.73
So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.
Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.
You will need the equation PV = nRT
P = Pressure in kPa
V = Volume in L
n = moles
R = 8.314 (constant)
T = Temperature in Kelvin
First convert 2.5 atm into kPa:
2.5 X 101.3 = 253.25 kPa
Convert 125 Celsius into Kelvin:
125 + 273 = 398 K
Convert Gallons to Litres:
1.25 X 3.79 = 4.74 L
Plug your values into the equation to solve for n:
(253.25)(4.74) = n(8.314)(398)
n = (253.25)(4.74)/(8.314)(398)
n = 0.362 moles
Now use M = m/n to solve for the mass of O2
M = Molar Mass
M = mass
n= moles
32 = m/(0.362)
m = (32)(0.362)
m = 11.58g
