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scoundrel [369]
2 years ago
15

When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammoni

a gas will be produced? N2 (g) + 3H2 (g) yields 2NH3 (g)
Chemistry
1 answer:
ehidna [41]2 years ago
8 0
<span>If the gasses participates in the reaction, and they under the same temperature and pressure,  ratio of their volumes is equal to ratio of the moles of these gasses in the reaction.                               
                                            N2 (g) + 3H2 (g)-------> 2NH3 (g)   
from reaction                    3 mol                               2 mol   
from the problem               4.5L                                x L

x=4.5*⅔=9/3=3 L<span>
</span></span>
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ale4655 [162]

Answer:

Mass = 0.697 g

Explanation:

Given data:

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PV  = nRT

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Now we will compare the moles of hydrogen and ammonia:

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