Answer:
The answer is 100
Step-by-step explanation:
2 times 2=4 4 times 5=20 20 times 5/5 times 2=10 then add a zero
Answer:
The half-life of the radioactive substance is of 3.25 days.
Step-by-step explanation:
The amount of radioactive substance is proportional to the number of counts per minute:
This means that the amount is given by the following differential equation:

In which k is the decay rate.
The solution is:

In which Q(0) is the initial amount:
8000 counts per minute on a Geiger counter at a certain time
This means that 
500 counts per minute 13 days later.
This means that
. We use this to find k.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is of 3.25 days.
Answer:
-1
Step-by-step explanation:
Plug in given values
-4x + 5y + 6z
-4(-2) + 5(3) + 6(-4)
8 + 15 -24
23-24
-1
This is what I got as my answer. Hope it helps!
Answer: Im very sure the answer is
B
Step-by-step explanation: