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Lunna [17]
3 years ago
15

Zach needs to make a 2.75 m solution of NaOH(molar mass=40.00g/mol) using 350. g of water. What mass of NaOH should he dissolve

in the water to make this solution? Please show the steps
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
3 0
Molality = number of mol solute/ 1000 g solvent = (2.75 mol NaOH)/1000g water


\frac{2.75( mol NaOH)}{1000(g/ water)} = \frac{x (mol  NaOH)}{350(g/water)} 


,
x= \frac{2.75*350}{1000} = 0.963 (mol NaOH)

0.963 (mol NaOH)* \frac{40.00 (g NaOH)}{1 ( mol NaOH)} =38.5 (g NaOH)


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The reaction is represented as:

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