Answer:
e. 1.2 x 10²³
Explanation:
According to the problem, The current equation is given by:
Here time is in seconds.
Consider at t=0 s the current starts to flow due to battery and the current stops when the time t tends to infinite.
The relation between current and number of charge carriers is:
Here the limits of integration is from 0 to infinite. So,
q = 1.90 x 10⁴ C
Consider N be the total number of charge carriers. So,
q = N e
Here e is electronic charge and its value is 1.69 x 10⁻¹⁹ C.
N = q/e
Substitute the suitable values in the above equation.
N = 1.2 x 10²³
Answer:
20m/s due east
Explanation:
Given parameters:
Displacement eastward = 200m
Time = 10s
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by time;
Velocity =
Velocity = = 20m/s due east
Answer:
C) must be such as to follow the magnetic field lines.
Explanation:
Ampere's circuital law helps us to calculate magnetic field due to a current carrying conductor. Magnetic field due to a current forms closed loop around the current . If a net current of value I creates a magnetic field B around it , the line integral of magnetic field around a closed path becomes equal to μ₀ times the net current . It is Ampere's circuital law . There may be more than one current passing through the area enclosed by closed curve . In that case we will take net current by adding or subtracting them according to their direction.
It is expressed as follows
∫ B.dl = μ₀ I . Here integration is carried over closed path . It may not be circular in shape. The limit of this integration must follow magnetic field lines.
the term ∫ B.dl is called line integral of magnetic field.
Answer:
Facilitated diffusion.
Explanation:
Facilitated diffusion is the movement of molecules across a biological cell membrane by the use of a membrane protein.
It is a spontaneous passive movement and it can also be reffered to as FACILITATED TRANSPORT or PASSIVE-MEDIATED TRANSPORT.
Answer:
The period will be doublef because increasing the mass increases the period linearly.
Explanation:
A stiffer spring with a constant mass decreases the period of oscillation. Increasing the mass increases the period of oscillation