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larisa [96]
3 years ago
5

I’ll give brainliest and 10 points

Physics
1 answer:
leonid [27]3 years ago
7 0

Answer:

what's these its D okkkk

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Two pianos each sound the same note simultaneously, but they are both out of tune. On a day when the speed of sound is 349 m/s,
SSSSS [86.1K]

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Time period between the successive beats will be 0.1703 sec

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We have given speed of the sound v = 349 m/sec

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Frequency of piano B f_2=\frac{v}{\lambda _1}=\frac{349}{0.776}=449.74Hz

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So time period T=\frac{1}{f}=\frac{1}{5.87}=0.1703sec

So time period between the successive beats will be 0.1703 sec

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