All categories

3 years ago

Jess rides her motorcycle at an average speed of 20 m/s for 500 seconds. how far did she ride

Physics

1 answer:

Sedaia [141]3 years ago

5 0

Distance = (speed) x (time)

Distance = (20 m/s) x (500 s)

Distance = (20 x 500) (m·s / s)

Distance = 10,000 m

You might be interested in

When an object is electrically polarized

marta [7]

Answer:

One side is more positive, the other is more negative

Explanation:

When an atom is electrically polarized, it means that one side has more electrons than the other. This makes one side more negative as it has more electrons than the other. I hope this helps!

5 0

3 years ago

Which statement is true? Hydroelectric power is generated from moving water. Oil, a renewable resource, is processed to make jet

Mrac [35]

Answer: hydroelectric power is generated from moving water

Explanation: hydroelectric power is generated from moving water

6 0

3 years ago

Read 2 more answers

a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion o

Dvinal [7]

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

7 0

2 years ago

Please<br>help<br>me<br>with this problem

uranmaximum [27]

Answer:

speeding up

Explanation:

because its speeding up, theres going to be more newtons in the back

i really hope this is right, tell me if so

3 0

2 years ago

At a time t = 2.80 s , a point on the rim of a wheel with a radius of 0.230 m has a tangential speed of 51.0 m/s as the wheel sl

bonufazy [111]

Answer:

Part A) the angular acceleration is α= 44.347 rad/s²

Part B) the angular velocity is 195.13 rad/s

Part C) the angular velocity is 345.913 rad/s

Part D ) the time is t= 7.652 s

Explanation:

Part A) since angular acceleration is related with angular acceleration through:

α = a/R = 10.2 m/s² / 0.23 m = 44.347 rad/s²

Part B) since angular acceleration is related

since

v = v0 + a*(t-t0) = 51.0 m/s + (-10.2 m/s²)*(3.4 s - 2.8 s) = 44.88 m/s

since

ω = v/R = 44.88 m/s/ 0.230 m = 195.13 rad/s

Part C) at t=0

v = v0 + a*(t-t0) = 51.0 m/s + (-10.2 m/s²)*(0 s - 2.8 s) = 79.56 m/s

ω = v/R = 79.56 m/s/ 0.230 m = 345.913 rad/s

Part D ) since the radial acceleration is related with the velocity through

ar = v² / R → v= √(R * ar) = √(0.23 m * 9.81 m/s²)= 1.5 m/s

therefore

v = v0 + a*(t-t0) → t =(v - v0) /a + t0 = ( 1.5 m/s - 51.0 m/s) / (-10.2 m/s²) + 2.8 s = 7.652 s

t= 7.652 s

4 0

3 years ago