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Troyanec [42]
3 years ago
6

Which is the correct expression for Keq when the chemical reaction is as follows:

Chemistry
2 answers:
zhuklara [117]3 years ago
4 0
The expression of the Keq is [NH3]2/([N2][H2]3). The common formula of reaction: ax+by=cz is Keq - [z]c/([x]a*[y]b). Remember to use a balanced chemical reaction.
skelet666 [1.2K]3 years ago
3 0

Answer : The expression for equilibrium constant will be,

K_{eq}=\fac{[NH_3]^2}{[N_2][H_2]^3}

Explanation :

Equilibrium constant : It is defined as the number of ratio of the concentration between the products and the reactants at equilibrium.

The equilibrium reaction is,

aX+bY\rightleftharpoons cW+dZ

The general expression for equilibrium constant will be,

K_{eq}=\frac{[X]^a[Y]^b}{[W]^c[Z]^d}

The given balanced chemical reaction will be,

N_2+3H_2\rightleftharpoons 2NH_3

The expression for equilibrium constant will be,

K_{eq}=\frac{[NH_3]^2}{[N_2][H_2]^3}

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