Question

Which is the correct expression for Keq when the chemical reaction is as follows:

Answer 1

The expression of the Keq is [NH3]2/([N2][H2]3). The common formula of reaction: ax+by=cz is Keq - [z]c/([x]a*[y]b). Remember to use a balanced chemical reaction.

Answer 2

Answer : The expression for equilibrium constant will be,

$K_{eq}=\fac{[NH_3]^2}{[N_2][H_2]^3}$

Explanation :

Equilibrium constant : It is defined as the number of ratio of the concentration between the products and the reactants at equilibrium.

The equilibrium reaction is,

$aX+bY\rightleftharpoons cW+dZ$

The general expression for equilibrium constant will be,

$K_{eq}=\frac{[X]^a[Y]^b}{[W]^c[Z]^d}$

The given balanced chemical reaction will be,

$N_2+3H_2\rightleftharpoons 2NH_3$

The expression for equilibrium constant will be,

$K_{eq}=\frac{[NH_3]^2}{[N_2][H_2]^3}$