Answer:
0.34 x 10^-3 m^3
Explanation:
P1 = 6 x 10^5 N/m^2
T1 = 10 degree C = 10 + 273 = 283 K
T2 = 35 degree c = 35 + 273 = 308 K
Pressure remains constant , P2 = P1
P1 V1 = R T1
V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3
Now, let the Volume is V2
P1 V2 = R T2
V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3
Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3
Those two units can be compared to a 'mile per hour' and a 'mile per hour - hour'.
One is a rate. The other is a quantity, after maintaining a rate for some time.
-- 'Joule' is a unit of energy. It's the amount of work (energy) you do
when you push with a force of 1 newton though a distance of 1 meter.
Lifting 10 pound of beans 3 feet off the floor takes about 40.7 joules of energy.
-- 'Watt' is a <u><em>rate</em></u> of using energy . . . 1 joule per second.
If you lift 10 pounds 3 feet off the floor in 1 second, your <em>power</em> is 40.7 watts.
-- 'Watt-second' is the amount of energy used in one second,
at the rate of 1 joule per second . . . 1 joule.
-- 'Watt-hour' is the amount of energy used in one hour,
at the rate of 1 joule per second . . . 3,600 joules.
-- 'Kilowatt' is a bigger <em>rate</em> of using energy . . . 1,000 joules per second.
-- 'Kilowatt - second' is the amount of energy used in one second,
at the rate of 1,000 joules per second . . . 1,000 joules .
-- 'Kilowatt - hour' is the amount of energy used in one hour,
at the rate of 1,000 joules per second . . . 3,600,000 joules .
Depending on where you live, 3,600,000 joules of energy bought
from the electric company costs something between 5¢ and 25¢.
When storm clouds produce lightening and thunder, then, potential energy changes into kinectic energy.
The clouds become negatively charged,and the ground is positively charged during a storm. So there creates a potential difference between the charged clouds and the ground. And when this becomes huge so much that it over comes the electrical insulation cover of air, the electrons jump to the ground.i.e. the potential energy changes into kinetic energy.
Is there specific factors I have to choose from?
Because energy is wasted either in the form of heat energy or something else (like friction)