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Oksanka [162]
4 years ago
14

I need help, please answer

Physics
1 answer:
Burka [1]4 years ago
7 0

This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.

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Please solve the Problem.
prisoha [69]

The scalar reading during the process is 170. 5 Newton

<h3>How to determine the scalar reading</h3>

force = mass × acceleration

Given the mass = 55kg

In finding the acceleration, use the first equation of motion

v = u + at

u = 0

t = 2s

v = 6.5 m/s

Substitute the values

6.5 = 0 + 2a, make 'a' the subject

a = 6. 5÷ 2 = 3. 1 m/s²

Substitute the value of 'm' and 'a' in the original equation

F = 55× 3.1 = 170. 5 Newton

Hence, the scalar reading during the process is 170. 5 Newton

Learn more about force here:

brainly.com/question/13164598

#SPJ1

7 0
2 years ago
If the force of gravity was suddenly removed between the earth and sun, how would Earth move?
dimaraw [331]

Answer:

the earthe would fly off into space in a straight line

6 0
3 years ago
A proton of mass 1.67×10-27 kg is being accelerated along a straight line at 7.01×1015 m/s2 in an accelerator. If the proton has
Masja [62]

Answer:

v_f=7*10^7\frac{m}{s}

Explanation:

The proton is under a linear motion with constant acceleration. So, we use the kinemtic equations to calculate its final speed. We know its acceleration, its initial speed and its traveled distance. Thus, we use the following equation:

v_f^2=v_0^2+2ax\\v_f=\sqrt{v_0^2+2ax}\\v_f=\sqrt{(6.63*10^7\frac{m}{s})^2+2(7.01*10^{15}\frac{m}{s^2})(3.63*10^{-2}m)}\\v_f=7*10^7\frac{m}{s}

5 0
4 years ago
A puddle dries up by the process of
levacccp [35]
The puddle dries up cause of the radiation from the sun
4 0
3 years ago
The magnitude​ R, measured on the Richter​ scale, of an earthquake of intensity I is defined as Requalslog StartFraction Upper I
lapo4ka [179]

Answer:

R = 6.8

Explanation:

Given data:

Richter scaleR = log(\frac{I}{I_o})

where R - magnitude of earthquake of Richter scale

I - quake's intensity =  10^{6.8} \times I_o

I_o - minimum intensity earthquake

Plugging all information in the equation to get Richter's scale

R = log(\frac{10^{6.8} \times I_o}{I_o})

R = log(10^{6.8})

R = 6.8

6 0
3 years ago
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