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nordsb [41]
4 years ago
5

9.

Chemistry
1 answer:
777dan777 [17]4 years ago
7 0

Answer:

salt in the Dead Sea is sodium chloride

while salt in the lab is either soluble or

insoluble in water.

Explanation:

The term 'salt' in the school laboratory does not always refer to sodium chloride. It is a generic term used for many substances especially those substances formed by neutralization reaction.

There are many salts that are used in the laboratory. Some of these salts are soluble in water while some are not soluble in water.

Salt in the dead sea always refers to sodium chloride, hence, salt in the dead sea is different from salt in the school laboratory.

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Mr. Summers observed that kids with hot dogs are happy. This observation led to a hypothesis that hot dogs must make kids happy.
Maslowich

Given what we know, we can confirm that since Mr. Summers has to test a hypothesis, his next step should be to design an experiment.

<h3>Why design an Experiment?</h3>
  • The next step is to design an experiment.
  • This is because Mr. Summers has already made an observation and created a problem.
  • He must now gather data to be analyzed.
  • In order to do this, he must first design and perform an experiment.

Therefore, we can confirm that Mr. Summers must design an experiment given that this is the best way to gather data in order to be analyzed in the future and draw a valid conclusion.

To learn more about Hypothesis visit:

brainly.com/question/2695653?referrer=searchResults

8 0
2 years ago
What mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid?
VMariaS [17]

Given :

2.5 mole of Sulfuric acid ( H_2SO_4 ) .

To Find :

Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid

Solution :

Let us assume volume of water be 1 L .

Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .

So , for 2.5 mole sulfuric acid required 5 mole of NaOH .

Moles of NaOH ,

n=M\times Volume \\\\n=5\times 1=5\ moles  

Molecular mass of NaOH , M.M = 58.44 g/mol .

Mass of 5 moles of NaOH :

m=5\times 58.44\ g\\\\m=292.2\ g

Hence , this is the required solution .

7 0
3 years ago
A sample of helium gas is placed in a rigid cylinder that has a movable piston. The volume of the gas is varied by moving the pi
Nataliya [291]
Helium is a light gas.  Movement can be predicted by which chamber has the lighter gas(es) and which chamber has the heavier.  constant changes can also be a variable.  If the gas is constant, then changes are more easily predicted.
5 0
3 years ago
Read 2 more answers
43 mg = [?]g <br>A. 0.043 g <br>B. 4.3 g <br>C. 4300 g <br>D. 43,000 g​
Ymorist [56]

Answer:

Option A (0.043 g) is the correct answer.

Explanation:

Given:

= 43 mg

As we know,

1 \ mg = \frac{1}{1000} \ g

then,

⇒ 43 \ mg = \frac{43}{1000}  \ g

              = 0.043 \ g

Thus, the above is the correct alternative.

4 0
3 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
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