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4 years ago

9.

Chemistry

1 answer:

777dan777 [17]4 years ago

7 0

Answer:

salt in the Dead Sea is sodium chloride

while salt in the lab is either soluble or

insoluble in water.

Explanation:

The term 'salt' in the school laboratory does not always refer to sodium chloride. It is a generic term used for many substances especially those substances formed by neutralization reaction.

There are many salts that are used in the laboratory. Some of these salts are soluble in water while some are not soluble in water.

Salt in the dead sea always refers to sodium chloride, hence, salt in the dead sea is different from salt in the school laboratory.

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compare and contrast the benefits with the potential negative effects of utilizing hydraulic fracturing to produce oil.

aleksandr82 [10.1K]

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3 years ago

8. A foot describes what characteristic of measurement?

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Answer:

It describes length of measurement...

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3 years ago

A graduated cylinder is filled with 60.0 ml of water. A cube, made of aluminum, is carefully dropped into the cylinder. Aluminum

katen-ka-za [31]

Answer:

65 ml

Explanation:

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2 years ago

2Na(s) + 2H,O(l) — 2NaOH(?) + H, (g) 0 what is the missing symbol

Klio2033 [76]

Answer:

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Explanation:

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3 0

3 years ago

The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re

Kitty [74]

Answer: The temperature of the system will be 1622 K

Explanation:

The equation relating the pre-exponential factor and activation energy follows:

$\log D=\log D_o-\frac{E_a}{2.303RT}$

where,

D = diffusion coefficient = $2.7\times 10^{-14}m^2/s$

$D_o$ = pre-exponential constant = $1.7\times 10^{-5}m^2/s$

$E_a$ = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

$\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K$

Hence, the temperature of the system will be 1622 K

8 0

3 years ago