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4 years ago

9.

Chemistry

1 answer:

777dan777 [17]4 years ago

7 0

Answer:

salt in the Dead Sea is sodium chloride

while salt in the lab is either soluble or

insoluble in water.

Explanation:

The term 'salt' in the school laboratory does not always refer to sodium chloride. It is a generic term used for many substances especially those substances formed by neutralization reaction.

There are many salts that are used in the laboratory. Some of these salts are soluble in water while some are not soluble in water.

Salt in the dead sea always refers to sodium chloride, hence, salt in the dead sea is different from salt in the school laboratory.

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Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward s

Simora [160]

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

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3 years ago

Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a phot

zzz [600]

Answer : The frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : $(1nm=10^{-9}m)$

So, the wavelength of the radiation = 670.8 nm = $670.8\times 10^{-9}m$

Now we have to calculate the frequency of a photon of radiation.

Formula used : $\nu =\frac{c}{\lambda}$

where,

$\nu$ = frequency of a photon of radiation

$\lambda$ = wavelength of the radiation

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

$\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}$

$\nu =4.47\times 10^9s^{-1}$

Therefore, the frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

6 0

4 years ago

Read 2 more answers

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$