What are 3 different forces that act on objects on the earth

Two point charges totaling 8 μC exert a repulsive force of 0.15 N on one another when separated by 0.5 m. What is the charge on

nexus9112 [7]

Answer:

B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C

Explanation:

From Coulomb's Law the electrostatic repulsive force is given by the following formula:

F = kq₁q₂/r²

where,

F = Repulsive Force = 0.15 N

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = Magnitude of 1st Charge = ?

q₂ = Magnitude of 2nd Charge = ?

r = Distance between Charges = 0.5 m

Therefore,

0.15 N = (9 x 10⁹ N.m²/C²)q₁q₂/(0.5 m)²

q₁q₂ = (0.15 N)(0.5 m)²/(9 x 10⁹ N.m²/C²)

q₁q₂ = 4.17 x 10⁻¹²

q₁ = (4.17 x 10⁻¹²)/q₂ -------------------- equation (1)

The sum of charges is given as:

q₁ + q₂ = 8 μC

q₁ + q₂ = 8 x 10⁻⁶

using equation (1):

(4.17 x 10⁻¹²)/q₂ + q₂ = 8 x 10⁻⁶

(4.17 x 10⁻¹²) + q₂² = 8 x 10⁻⁶ q₂

q₂² - (8 x 10⁻⁶) q₂ + (4.17 x 10⁻¹²) = 0

Solving this quadratic equation:

q₂ = 7.4 x 10⁻⁶ C (OR) q₂ = 0.56 x 10⁻⁶ C

q₂ = 7.4 μC (OR) q₂ = 0.6 μC

Therefore,

q₁ = (4.17 x 10⁻¹² C)/(7.4 x 10⁻⁶ C)

q₁ = 0.6μC

Now, if we solve with q₂ = 0.6 μC, we will get q₁ = 7.4 μC.

Therefore, the correct option will be:

8 0

3 years ago

An arcade ball is thrown with an initial speed of 7.0 m/s and follows the trajectory shown. The ball enter the basket .95 second

dmitriy555 [2]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

$x = 4.70 \ m$ , $y = 0.2803 \ m$

Explanation:

From the question we are told that

The initial velocity of the arcade ball is $u = 7.0 \ m/s$

The time taken by the ball to enter the basket is $t = 0.95 \ s$

Generally the x -component of the initial velocity is

$u_x = 7 * cos (45)$

=> $u_x = 4.95 \ m/s$

Generally the y -component of the initial velocity is

$u_x = 7 * sin(45)$

=> $u_y = 4.95 \ m/s$

Generally the distance x is mathematically represented as

$x = u_x * t$

=> $x = 4.95 * 0.95$

=> $x = 4.70 \ m$

Generally from kinematic equation the distance y is mathematically represented as

$y = u_y * t - \frac{1}{2} * g * t^2$

=> $y = 4.95 * 0.95 - \frac{1}{2} * 9.8 * 0.95^2$

=> $y = 0.2803 \ m$

7 0

3 years ago

Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 22 N

klemol [59]

We have: A= F.s
So, A = 22 x 16
A= 352J
Só A is correct answer

3 0

3 years ago

Read 2 more answers

Which organelle in the plant cell would mainly help the cell get rid of water and how do you know

stiks02 [169]

The vacuole, its main job is to get rid of waste and water inside the cell.

8 0

3 years ago

If you push a box across a horizontal floor towards the south, in which direction will friction act?

MrRissso [65]

Answer: North

Explanation: I believe the friction will go the opposite way of the object being pushed.

3 0

2 years ago