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3 years ago

Longer wavelengths will have frequencies, and shorter wavelengths will have frequencies.

1 answer:

3 0

Within a single medium, the product of (wavelength) x (frequency)
is always the same number, for all waves. (It's the wave-speed.)

This means that longer wavelengths must have lower frequencies,
and shorter wavelengths must have higher frequencies, in order for
the product to always come out to be the same.

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Movement of a molecule against its concentration gradient can occur through Select one or more: a. facilitated diffusion b. pass

uranmaximum [27]

Answer:

The answer to your question is:

Explanation:

There are two kinds of cell transport passive transportation and active transportation.

Passive transportation does not need energy because molecules move from higher concentration to lower concentration.

Active transportation needs energy because molecules moves against concentration.

a. facilitated diffusion It's an example of passive transportation so this answer is wrong.

b. passive transport Molecules move in favor of concentration so this answer is wrong.

c. osmosis is another example of passive transport so this answer is wrong.

d. simple diffusion it's another example of passive transport, so it's wrong this answer.

e. active transport this is the right answer.

5 0

3 years ago

Calculate the de Broglie wavelength of (a) a mass of 1.0 g traveling at 1.0 m s−1 , (b) the same, traveling at 1.00 × 105 km s−1

lesantik [10]

Answer:

a) $\lambda=6.63\times10^{-31}m$

b) $\lambda=6.63\times10^{-39}m$

c) $\lambda=9.97\times10^{-11}m$

d) $\lambda=4.03\times10^{-36}$ m

e)λ=∞

Explanation:

De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

$\lambda=\frac{h}{P}=\frac{h}{mv}$

with h the Plank's constant ( $6.63\times10^{-34}\frac{m^{2}kg}{s}$ ) and P the momentum of the object that is mass (m) times velocity (v).

a) $\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}$

$\lambda=6.63\times10^{-31}m$

b) $\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}$

$\lambda=6.63\times10^{-39}m$

c) $\lambda=\frac{6.63\times10^{-34}}{(6.65\times10^{-27}*1000)}$

$\lambda=9.97\times10^{-11}m$

d) $\lambda=\frac{6.63\times10^{-34}}{(74*2.22)}$

$\lambda=4.03\times10^{-36}$ m

e) $\lambda=\frac{6.63\times10^{-34}}{(74*0)}$

λ=∞

6 0

3 years ago

Which of the following is NOT a good example of a short-term goal?

Molodets [167]

Loose 10 pounds im pretty sure

5 0

3 years ago

2 rocks of different masses roll down a hill at the same speed which rock has more kinetic energy small one or big one ???

Sophie [7]

Kinetic energy depends on the mass and the speed of a moving object.

If the speeds are equal, then the rick with more mass has more kinetic energy.

5 0

3 years ago

Read 2 more answers

Suppose a ceiling fan has a mass of 7.5 kg and is 9.7 m above the ground. What is the gravitational potential energy of the ceil

EleoNora [17]

The gravitational potential energy (G.P.E) of the ceiling fan is 712.95 Joules.

<u>Given the following data:</u>

Mass of ceiling fan = 7.5 kg

Height = 0.7 m

<u>Scientific data:</u>

Acceleration due to gravity = 9.8 $m/s^2$

To calculate the gravitational potential energy (G.P.E) of the ceiling fan:

<h3>What is gravitational potential energy?</h3>

Gravitational potential energy (G.P.E) can be defined as the energy that is possessed by an object or body due to its position (height) above planet Earth.

Mathematically, gravitational potential energy (G.P.E) is given by this formula;

$GPE = mgh$

<u>Where:</u>

G.P.E is the gravitational potential energy.

m is the mass of an object.

g is the acceleration due to gravity.

h is the height of an object.

Substituting the given parameters into the formula, we have;

$GPE = 7.5 \times 9.8 \times 9.7$

GPE = 712.95 Joules.

Read more on potential energy here: brainly.com/question/8664733

8 0

2 years ago

Longer wavelengths will have ________ frequencies, and shorter wavelengths will have ________ frequencies.

Longer wavelengths will have frequencies, and shorter wavelengths will have frequencies.