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den301095 [7]
3 years ago
7

You push the ball with aforce of 22.8N which induces a -2.3N frictional force. What is the net force while you push?

Physics
1 answer:
inna [77]3 years ago
5 0
The net force is 22.8-2.3 or 20.5 N
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At a certain instant, coil A is in a 10-T external magnetic field and coil B is in a 1-T external magnetic field. Both coils hav
motikmotik

Answer:

Impossible to know without more information about the fields.

Explanation:

Changing the magnetic field induces the external magnetic field, but the information regarding magnetic field variation is not provided. We need to required more information for this

Therefore according to the above explanation the correct option is Impossible to know without more information about the fields.

Hence, the b option is correct

3 0
3 years ago
(1) In nondestructive testing, a discontinuity may be defined as an interruption in the normal physical structure or configurati
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Answer: BOTH ARE TRUE

Explanation: Nondestructive testing or Evaluation is a term used in the field of science and technology to describe the evaluations, analysis or testing carried out on components of materials without destroying any part or components of the test materials. It is very useful in scientific research or industrial engineering environments. When any disruption of physical structure or configuration of a component will lead to discontinuing of the test, and it may not affect the usefulness of the affected parts.

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3 years ago
Label the different parts of a heart:
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Here hope this helps:)

4 0
4 years ago
A person who weighs 150 pounds on Earth would weigh ____ pounds on the moon.
enot [183]

Answer:

25lb

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You haven't changed (you are made up of the same atoms), but the force exerted on you is different. Physicists like to say that your mass hasn't changed, only your weight.

6 0
3 years ago
3
german

Answer:

The time taken by the ship to cover the distance, t = (x/25)  s

Explanation:

Given data,

The initial velocity of the ship, u = 20 m/s

The final velocity of the ship, v = 30 m/s

The average velocity of the ship, V = (20 + 30)/ 2

                                                           = 25 m/s

The distance covered by the ship, d = x m

Then the time taken by the ship to cover the displacement is,

                   d =  V x t

∴                   t = d / V

Substituting the values,

                     t = x / 25

                     t = (x/25)  s

Hence, the time taken by the ship to cover the distance, t = (x/25) s

4 0
3 years ago
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