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xxTIMURxx [149]
3 years ago
8

At what common temperature will a block of wood and a block of metal both feel neither hot nor cold to the touch? 1. when the te

mperature of the blocks is higher than the temperature of your hand 2. when the temperature of the blocks is the same as the temperature of your hand 3. when the temperature of the blocks is lower than the temperature of your hand 4. at room temperature 5. at the freezing point
Physics
1 answer:
My name is Ann [436]3 years ago
3 0
I believe 2. is the correct answer
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If an airplane is flying at 300 km/h to the east and is facing a headwind of 18.0 km/h, what is the airplane's final velocity?
givi [52]
If an airplane is flying at 300 km/h to the east and is facing a headwind of 18.0 km/h, the final velocity can be calculated using simple vector addition. In this case, the planes velocity is positive (+330 km/h) and head wind has a negative component (-18.0 km/h). Vector addition yields +330 km / h + (-18.0 km /h) = 312 km / h. 
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3 years ago
Meteorologists classify tropical cyclones using a measurement of sustained winds within the low-pressure system. How do meteorol
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Explanation:

It is a 1-minute averaged measure of the hurricane's maximum winds. Westerlies are one of the breeze belts helping to shape and guide hurricanes. A tropical cyclone is a quickly spinning storm system with a low-pressure core, a closed small-level air vortex, gusty winds, and a thunder storm spiral structure that causes torrential rain or squalls.

3 0
3 years ago
A cold glass is left sitting outside on a hot day. Soon, water droplets form on the outside of the glass. Describe the events th
ikadub [295]
Evaporation must happen
8 0
3 years ago
Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit
Elodia [21]

As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

\Delta KE = \Delta PE

\frac{1}{2}mv_f^2-\frac{1}{2} mv_0^2 = mgh_2-mgh_1

Where,

m = mass

v_{f,i} = initial and final velocity

g = Gravity

h = height

As the mass is tHe same and the final height is zero we have that the expression is now:

\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2

\frac{1}{2} (v_f^2-v_0^2) = gh_2

(v_f^2-v_0^2) = 2gh_2

v_f = \sqrt{2gh_2+v_0^2}

v_f = \sqrt{2(9.8)(23.5)+13.6^2}

v_f = 25.4m/s

7 0
3 years ago
If a plane has an airspeed of 40 m/s and is experiencing a crosswind of 30 m/s, what is its ground speed in m/s?
Anon25 [30]
<h2>Answer:50ms^{-1}</h2>

Explanation:

Let v_{a} be the airspeed.

Let v_{w} be the cross wind speed.

We know that,ground speed is the vector sum of airspeed and cross wind speed and airspeed is perpendicular to cross wind speed.

If v_{1} and v_{2} are two perpendicular vectors,the resultant vector has the magnitude \sqrt{|v|_{1}^{2}+|v|_{2}^{2}}

Given,

v_{a}=40ms^{-1}\\v_{c}=30ms^{-1}

So,the ground speed is \sqrt{40^{2}+30^{2}}=\sqrt{2500}=50ms^{-1}

6 0
3 years ago
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