Answer:
The moment of inertia I is
I = 2.205x10^-4 kg/m^2
Explanation:
Given mass m = 0.5 kg
And side lenght = 0.03 m
Moment of inertia I = mass x radius of rotation squared
I = mr^2
In this case, the radius of rotation is about an axis which is both normal (perpendicular) to and through the center of a face of the cube.
Calculating from the dimensions of the the box as shown in the image below, the radius of rotation r = 0.021 m
Therefore,
I = 0.5 x 0.021^2 = 2.205x10^-4 kg/m^2
Susie's vertical displacement is 2.1 m
Explanation:
In order to solve this problem, we have to resolve the displacement vector along the vertical direction.
The vertical component of a vector is given by:
where
v is the magnitude of the vector
is the angle between the direction of the vector and the horizontal
Therefore, the vertical component of the displacement in this problem is given by
where
d = 3 m is the magnitude of the displacement
is the angle between the displacement and the horizontal
Substituting, we find
Learn more about vector components:
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Answer:
P = 5880 J
Explanation:
Given that,
The mass of a person, m = 60 kg
The height of the stairs, h = 10 m
We need to find the gravitational potential energy of the person. The formula is as follows :
Substitute all the values,
So, the required gravitational potential energy is equal to 5880 J.