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andreev551 [17]
3 years ago
11

Since all objects are ‘weightless’ for an astronaut in orbit, is it possible for astronauts to tell whether an object is heavy o

r light? Think about it, think of newton’s laws, the equations and then explain your reasoning.
Physics
2 answers:
ivanzaharov [21]3 years ago
4 0
W=gm
where g - gravitation 
m - mass
w - weight
as gravitation equals to zero, multiplying by 0 gives W=0
It is not possible to tell whether and object is heavy or light 

ValentinkaMS [17]3 years ago
4 0
Well, while they're in orbit, nothing is 'heavy' and nothing is 'light'.
They're all weightless.

I think you're really asking:  Can the astronaut tell which objects will be
heavy and which ones will be light if they go back down to Earth ?

The answer is a resounding 'Sure' !

The weight of an object on Earth is (its mass) x (acceleration of gravity).
So the objects with a lot of mass will be heavy, and the objects with less
mass will be lighter.

How can the astronaut determine the mass of the object hanging there
in the air in front of him ? 
All he has to do is give it a push.  It'll accelerate away from him (and he
will accelerate away from the object). 
Newton's 2nd law tells us that  F=mA, so the acceleration will be

                             (the force he exerts) / (the mass).

An object with small mass will zip away from him, and it'll be light
down on the surface. 

An object with large mass will accelerate slightly, start moving slowly,
and it'll be heavy down on the surface.
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Answer:

13.2 meters

Explanation:

(5.4) + (7.8)

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A team of seven psychologist is study love, but each psychologist is working from a different perspective. In your opinion, what
stepladder [879]

Answer:

- Behavioral Psychologists

- Psychodynamic Psychologist

- Biological Psychologist

- Cognitive Psychologist

- Evolutionary Psychologist

- Socio - Cultural Psychologist

- Humanist Psychologist

Explained in explanation section

Explanation:

There are different classes of psychologists but for the purpose of this question we need just 7 that would fit into the study of love. These 7 will be;

1) A behavioral Psychologist might study behaviors associated with love, such as hugging, caressing or kissing.

2) A psychodynamic psychologist might study how a people's challenges with love are caused by unmindful and unresolved conflicts.

3) A biological psychologist might study which chemicals in the brain such as dopamine make people feel loved. He might also study parts of the what parts of the brain are active when people are in love.

4) A cognitive psychologist might study how people's cognitive processes will change when they are in love.

5) An evolutionary psychologist might study how certain actions or behaviors associated with love provided our forefathers with sufficient knowledge to handle their love problems.

6) A sociocultural psychologist might study how people express love in in various cultures across the world.

7) A humanistic psychologist might study the behavior of those who feel most loved and the impact it has in their lives

8 0
3 years ago
A 1000-kg car moving at 10 m/s brakes to a stop in 5 s. the average braking force is
Marina86 [1]
To calcculate the braking force of the car moving, we use Newton's second law of motion which relates the acceleration and the force of an object moving. The force of an object moving is directly proportional to its acceleration and the proportionality constant is the mass of the object. It is expressed as:

Force = ma

Acceleration is the rate of change of the velocity of a moving object. We calculate acceleration from the velocity and the time given above.

a = (10 m/s) / 5 s = 2 m/s^2

So,
Force = ma
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Force = 2000 kg m/s^2 or 2000 N
4 0
3 years ago
A person throws a ball straight up. He releases the ball at a height of 1.75 m above the ground and with a velocity of 12.0 m/s.
Lyrx [107]

Answer:

a) 1.22 s

b) 9.089 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-12}{-9.81}\\\Rightarrow t=1.22\ s

Time taken by the ball to reach the highest point is 1.22 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=12\times 1.22+\frac{1}{2}\times -9.81\times 1.22^2\\\Rightarrow s=7.339\ m

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m

8 0
3 years ago
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