Answer:
31302 Volts and 55/111 Amps (≈0.5)
Explanation:
Secondary voltage / 141 = 1110 / 5
Secondary voltage = (1110*141) / 5
Secondary voltage = 31302
Amperage = 110/ (31302/141) = 55/111
Answer:
Average speed is 6m/s
Average velocity is 5.859m/s
Explanation:
Average speed, s = d/t
d is distant
t is time
speed north is 800m and 110s
speed due south is 400m and 90s
Average speed = (800+400) / (110+90)
= 1200/200
=6m/s
Average velocity V = (v + u)/2
v = final velocity
u = initial velocity
V = (7.273 + 4.444)/2 = 11.717/2
V = 5.859m/s
Answer:
The correct option is "In order to gain more power you would need to increase either current or voltage."
Explanation:
To answer the question, we note that;
The formula for Electrical Power are as follows,
P = I²·R, or P = I·V,
Therefore, if we increase either the current, I with the voltage, V remaining constant or we increase the Voltage, V with the current, I remaining constant or we increase both the voltage, V an the current, I the Power, P will be increased.
Therefore, the correct option is "In order to gain more power you would need to increase either current or voltage."
The mass of magnesium oxide must be 40 grams
Explanation:
The law of conservation of mass states that the total mass of the reactant in a chemical reaction must be equal to the total mass of the products after the reaction has completed.
In this problem, we have:
Reactants:
Magnesium metal (mass: 24 grams)
Oxygen gas (mass: 16 grams)
Products:
Magnesium oxide (mass: ?)
According to the law of conservation of mass, the mass of the magnesium oxide must be equal to the sum of the mass of the magnesium metal and the oxygen gass. Therefore:
Mass (magnesium oxide) = 24 g + 16 g = 40 g
Learn more about law of conservation of mass:
brainly.com/question/5017646
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