length of the grilling machine is 1.2 m
time taken to cook the burger is 2.7 min = 162 s
so the speed of the machine should be like this that if must have to cook till it cross the machine
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
![v = \frac{1.2}{162}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B1.2%7D%7B162%7D)
![v = 7.41* 10^{-3} m/s](https://tex.z-dn.net/?f=v%20%3D%207.41%2A%2010%5E%7B-3%7D%20m%2Fs)
now in one minute the total length of the machine that is covered is given by
![L = v*t](https://tex.z-dn.net/?f=L%20%3D%20v%2At)
![L = 7.41*10^{-3}* 60 = 44.4 cm](https://tex.z-dn.net/?f=L%20%3D%207.41%2A10%5E%7B-3%7D%2A%2060%20%3D%2044.4%20cm)
now distance between the burgers is 15 cm
so total production rate will be
![N = \frac{44.4}{15} = 3 burger/min](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B44.4%7D%7B15%7D%20%3D%203%20burger%2Fmin)
so it will produce 3 burger per minute
Hello there!
For this:
1). Convert 10km to meters!
2). Convert the 30 minutes into seconds!
3). Use the following formula to solve for speed!
speed= distance/time
Note: The units should automatically work out to m/s. :)
My goal is to make sure you understand the problem, which is why I won't be giving you the answer. It'll be more work now, but less work in the future! :)
Hope this helped!
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Answer:
164.87 J
Explanation:
From the question,
Work done (W) = mghcosθ........................ Equation 1
Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical
Given: m = 25 kg, h = 2.6 meters, θ = 75°.
Constant: g = 9.8 m/s²
Substitute these value into equation 1
W = 25×9.8×2.6×cos75°
W = 164.87 J.
-- In combination with 610 Hz, the beat frequency is 4 Hz.
So the unknown frequency is either (610+4) = 614 Hz
or else (610-4) = 606 Hz.
In combination with 605 Hz, the beat frequency will be
either (614-605) = 9 Hz or else (606-605) = 1 Hz.
-- In actuality, when combined with the 605 Hz, the beat
frequency is too high to count accurately. That must be
the 9 Hz rather than the 1 Hz.
So the unknown is (605+9) = 614 Hz.