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3 years ago

15

Megan and her brother are watching a television program. Megan notices that the television produces a lot of light. What else do

es the television produce?
A) chemical energy

B) heat energy

C) particles of matter

D) steam

1 answer:

lara [203]3 years ago

3 0

I do believe it’s heat !

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Identical twins Anna and Hannah visit you at the optical clinic. Anna, whose eyes can easily focus on distant objects (her far p

umka21 [38]

Answer:

c

Explanation:

from. 50 to 60 diopters

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4 years ago

Help me rearrange this formula. <br><br>I've been trying but I can't remember how to do it.

NikAS [45]

-- Multiply each side of the formula by 2

-- Then divide each side by t

-- Then subtract V(i) from each side.

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3 years ago

Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially

statuscvo [17]

Answer:

Final speed is 900.06 m/s at $0.2215^{\circ}$

Solution:

As per the question:

Mass of the first asteroid, m = $15\times 10^{3}\kg$

Mass of the second asteroid, m' = $20\times 10^{3}\kg$

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, $\theta = 20^{\circ}$

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

$\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}$

Thus applying vector addition and momentum conservation, the final velocity is given by:

$(m + m')v_{final} = \sqrt{(mv)^{2} + 2(mv)(m'v')cos20^{\circ} + (m'v')^{2}}$ (1)

Now,

$(m +m')v_{final} = (35\times 10^{3})v_{final}$

$(mv)^{2} = (15\times 10^{3}\times 770)^{2} = 1.334\times 10^{14}$

$(m'v')^{2} = (20\times 10^{3}\times 1020)^{2} = 4.16\times 10^{14}$

$2(mv)(m'v')cos20^{\circ} = 2(15\times 10^{3}\times 770)(20\times 10^{3}\times 1020)cos20^{\circ} = 4.43\times 10^{14}$

Now, substituting the suitable values in eqn (1), we get:

$v_{final} = 900.06\ m/s$

Now, the direction for the two vectors is given by:

$\theta = sin^{- 1} \frac{m'v'sin20^{\circ}}{(m + m')v_{final}}$

$\theta = sin^{- 1} \frac{20\times 10^{3}\times 1020sin20^{\circ}}{(35\times 10^{3})\times 900.06} = 0.2215^{\circ}$

5 0

3 years ago

A battery produces less electrical energy than the total amount of chemical energy contained in its reactive substances. Which s

labwork [276]

Answer:

The energy conversion does not fully occur due to various energy losses.

Explanation:

There are many different types of batteries, but all have three basic components: positive electrode (cathode, or "positive terminal"), negative electrode (anode or "negative terminal"), and electrolyte.

Charging a battery forces ions from cathode to anode; the battery reverses the flow. Over a period of time, this process wears out cathode, which results in reduced capacity.

Also there can be heat loss inside the system as well which is produced by the conversion from chemical energy.

Hence the chemical energy does not fully convert to electrical energy.

3 0

4 years ago

Determine the magnitude and direction of the force between two parallel wires 25 m long and 6.0 cm apart, each carrying 25 a in

mr Goodwill [35]

The magnetic force between two wires is 0.052 N which is attract each other.

We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is

F = μ₀ . I1 . I2 . L / ( 2π . r )

where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.

From the question above, we know that:

L = 25 m

r = 6 cm

I1 = I2 = 25 A

By substituting the parameter, we get

F = μ₀ . I1 . I2 . L / ( 2π . r )

F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)

F = 0.052 N

Hence, the force between two wires is 0.052 N which is attract each other.

Find more on magnetic force at: brainly.com/question/13277365

#SPJ4

7 0

2 years ago