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Zanzabum
3 years ago
6

which would you think would be a stronger interaction and why: an interaction between a sodium ion and the prtial negative charg

e on the oxygen in ethanol, or the interaction between two ethanol molecules
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

The interaction between sodium ion and the partial negative charge on the oxygen is stronger.

Explanation:

The predominant interaction that exists between sodium ion and the partial negative charge on the oxygen is ion-dipole interaction.

The predominant interaction that exists between two ethanol molecules is hydrogen bonding interaction.

The order of strength of the intermolecular interactions in decreasing order:

Ionic bond > ion-dipole interaction > hydrogen bonding > dipole-dipole interaction > ion-induced dipole interaction > induced dipole- dipole interaction > london force

So, ion-dipole interaction is stronger than hydrogen bonding.

Hence, the interaction between sodium ion and the partial negative charge on the oxygen is stronger.

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How do countries with different currencies trade goods with each other?
8090 [49]

Answer:

D- They use the exchange rate to convert one's Country's currency to another's

Explanation:

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2 years ago
Electron configurations are a shorthand form of an orbital diagram, describing which orbitals are occupied for a given element.
kipiarov [429]

Answer:

[Ar] 3d10 4s2 4p3 is shorthand, 1s22s22p63s23p63d104s24p3 long hang

Explanation:

The shorthand is made using the lowest & closest noble gas, and picking up where it leaves off as follows, and longhand is made from a followed pattern you can easily find

3 0
3 years ago
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an isotope of cesium (cesium-137) has a half-life of 30 years if 1.0g of cesium-137 disintegrates over a period of 90 years how
Juliette [100K]
The answer is after 3 half lives
4 0
3 years ago
At 73.0 ∘c , what is the maximum value of the reaction quotient, q, needed to produce a non-negative e value for the reaction so
damaskus [11]
Here we will use the general formula of Nernst equation:

Ecell = E°Cell - [(RT/nF)] *㏑Q

when E cell is cell potential at non - standard state conditions

E°Cell is standard state cell potential = - 0.87 V

and R is a constant = 8.314 J/mol K

and T is the temperature in Kelvin = 73 + 273 = 346 K

and F is Faraday's constant = 96485 C/mole

and n is the number of moles of electron transferred in the reaction=2  

and Q is the reaction quotient for the reaction 
SO42-2(aq) + 4H+(aq) +2Br-(aq) ↔  Br2(aq) + SO2(g) +2H2O(l)

so by substitution :

0 = -0.87 - [(8.314*346K)/(2* 96485)*㏑Q      → solve for Q 


∴ Q = 4.5 x 10^-26 
6 0
3 years ago
If a gas had a volume of 6.7 L and started at STP, what would the new pressure be
Phantasy [73]

The new pressure would be = 4.46 atm

<h3>Further explanation</h3>

Given

V₁=6.7 L(at STP, 1 atm 273 K)

V₂=1.5 L

Required

The new pressure

Solution

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

P₂ = (P₁V₁)/V₂

P₂ = (1 atm x 6.7 L)/1.5 L

P₂ = 4.46 atm

5 0
2 years ago
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