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3 years ago

Which of the following is the best example of heat transfer by convection

Chemistry

1 answer:

Ugo [173]3 years ago

6 0

B seems like the correct answer stay safe!

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How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

SVEN [57.7K]

<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u /> $3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )$ = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0

3 years ago

Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu

MAVERICK [17]

Answer : The initial temperature of system 2 is, $19.415^oC$

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

$-q_1=q_2$

$m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)$

The mass remains same.

where,

$C_1$ = heat capacity of system 1 = 19.9 J/mole.K

$C_2$ = heat capacity of system 2 = 28.2 J/mole.K

$T_f$ = final temperature of system = $30^oC=273+30=303K$

$T_1$ = initial temperature of system 1 = $45^oC=273+45=318K$

$T_2$ = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

$-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K$

$T_2=292.415K$

$T_2=292.415-273=19.415^oC$

Therefore, the initial temperature of system 2 is, $19.415^oC$

8 0

3 years ago

भारत के एक ही राज्य में लगातार सबसे लंबे समय तक

IgorLugansk [536]

Answer:

Explanation:

6 0

3 years ago

Please help me i will give brain list tap the question

mr_godi [17]

Answer:

molecular formulas of the hydrocarbons

6 0

3 years ago

Read 2 more answers

Student have a receipt which calls for 1.15 lb of flour, but, of course, in France you will need to purchase flour in kilograms.

Verizon [17]

0.52164 kg of Flour

<u>Explanation:</u>

We have to convert lb (pounds) kg (kilograms), by using the conversion unit,

1 lb = 0.4536 kg

So to convert 1.15 lb into kg, we have to multiply 1.15 by 0.4536.

$1.15 \times 0.4536$ = 0.52164 kg of Flour

So the receipt calls for 0.52164 kg of Flour.

5 0

3 years ago