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Ksenya-84 [330]
3 years ago
13

What mass of cl2 is required for the complete reaction

Chemistry
1 answer:
Alchen [17]3 years ago
7 0
My teacher had given us this map to solve these types of problems. Start with 10 g of iron, use the molar mass of iron, mole ratio to the next chemical ( in this case Cl2) and then use the molar mass of Cl2.
Hope this helps!

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How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *
serg [7]

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

Fraction remaining (FR) = 0.5n

n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

-1.81 = -0.301 n

n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

6 0
2 years ago
How many atoms of manganese are in 1.00 g?
andriy [413]

Answer:

\frac{1.00g}{54.9g. {mol}^{ - 1} }  =  0.0182\: mol\\  \\ 6.023 \times  {10}^{23}   \times 0.0182 \: mol  \\ = 0.109\times  {10}^{23} \: atoms

8 0
2 years ago
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Lisa [10]
What’s are the matters
4 0
2 years ago
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7 0
3 years ago
A mixture of 9.22 moles of A, 10.11 moles of B, and 27.83 moles of C is placed in a one-liter
AysviL [449]

The equilibrium constant is 1.3 considering the reaction as written in the question.

<h3>Equilibrium in chemical reactions</h3>

In a chemical reaction, the equilibrium constant is calculated based on the equilibrium concentration of each specie. The equation of this reaction is;

A (g) + 2B (g) ⇌ 3C (g).

The initial concentration of each specie is;

  • A - 9.22 M
  • B - 10.11 M
  • C - 27.83 M

The equilibrium concentration of B is 18.32 M

We now have to set up the ICE table as follows;

         A (g) +    2B (g) ⇌     3C (g)

I       9.22        10.11           27.83

C     -x              -x                +x

E   9.22 - x       10.11 - x       27.83 + x

The equilibrium concentration of B is 18.32 M hence;

10.11 - x = 18.32

x = 10.11 - 18.32 = -8.21

Hence;

Equilibrium concentration of A = 9.22 - (-8.21) = 17.43

Equilibrium concentration of C = 27.83 + (-8.21) = 19.62

Equilibrium constant K = [19.62]^3/[17.43] [18.32]^2

K = 1.3

Learn more about equilibrium constant: brainly.com/question/17960050

4 0
2 years ago
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