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Maksim231197 [3]
3 years ago
11

Which type of wave has a wave perpedicular to the disturbance? mechanical surface longitudinal tranverse

Physics
1 answer:
cricket20 [7]3 years ago
3 0
<span>Which type of wave has a wave perpedicular to the disturbance? Answer-D Tranverse

</span>
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How Can the human ear detect the sound
liq [111]

Explanation:

The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.

8 0
2 years ago
A racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision
Fudgin [204]

Answer:

The average acceleration of the ball during the collision with the wall is a=2,800m/s^{2}

Explanation:

<u>Known Data</u>

We will asume initial speed has a negative direction, v_{i}=-30m/s, final speed has a positive direction, v_{f}=26m/s, \Delta t=20ms=0.020s and mass m_{b}.

<u>Initial momentum</u>

p_{i}=mv_{i}=(-30m/s)(m_{b})=-30m_{b}\ m/s

<u>final momentum</u>

p_{f}=mv_{f}=(26m/s)(m_{b})=26m_{b}\ m/s

<u>Impulse</u>

I=\Delta p=p_{f}-p_{i}=26m_{b}\ m/s-(-30m_{b}\ m/s)=56m_{b}\ m/s

<u>Average Force</u>

F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}

<u>Average acceleration</u>

F=ma, so a=\frac{F}{m_{b}}.

Therefore, a=\frac{2800m_{b} \ m/s^{2}}{m_{b}} =2800m/s^{2}

8 0
3 years ago
How long did the trip from camp wood to the pacific ocean and back again take?
maria [59]

The trip from Camp Wood to the Pacific Ocean and back again took 1.5 years to complete.<span>

</span>

<span>The </span>Lewis<span> and Clark </span>Expedition<span> from May 1804 to September 1806, also known as the Corps of Discovery </span>Expedition, was the first American expedition<span> to cross what is now the western portion of the United States.</span>
6 0
3 years ago
Where do we use friction in day to day life​
laila [671]

Answer:

walking in ground

while playing carrom

7 0
2 years ago
What is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
Tamiku [17]

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \boxed{\lambda = V/f}

                                                   <u>Δ   Being   Δ</u>

                                            f = Frequency = 262 Hz

                                            v = Velocity = 343 m/s

                                             \lambda = Wavelenght = ?

⇒ Let's replace according the formula:

\boxed{\lambda = 343\ m/s / 262\ Hz }

⇒ Resolving

\boxed{\lambda = 1,3 \ m}

Result:

The wavelength is <u>1,3 meters.</u>

Good Luck!!

8 0
3 years ago
Read 2 more answers
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