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Lapatulllka [165]
3 years ago
13

What is the name of FeSO (with roman numerals)?

Chemistry
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

Iron(II) sulfate

Explanation:

Chemical equation of formation of FeSO₄:

Fe + H₂SO₄   →   FeSO₄ + H₂

The name of FeSO₄ is Iron(II) sulfate.

It is also called ferrous sulfate.

It is blue green crystalline solid.

It is odorless.

It is inorganic salt.

Its atomic mass is 151.908 g/mol.

Its density is 1.898 g/ml.

This salt is soluble in water.

The melting point of anhydrous ferrous sulfate is 680°C.

It is used in medicine in treatment of anemia.

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Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 417 mL .
bixtya [17]

Answer:

m = 1125.9 g.

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the definition of density as mass divided by volume:

d=\frac{m}{V}

Thus, we solve for the mass in the equation to obtain:

m=d*V

Then, we plug in the values to obtain:

m=2.70g/mL*417mL\\\\m=1125.9g

Regards!

5 0
3 years ago
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zhannawk [14.2K]

Answer: give me more of an explaination

Explanation:

3 0
3 years ago
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eimsori [14]

Answer:

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The answer is: 1. periodic table

4 0
3 years ago
Why is very important to wait until the crucible is fully coleed to room temperature before weighting
Mars2501 [29]

If you do not wait until the crucible is at room temperature, its density will vary constantly until it reaches this temperature, since density is a property that varies with temperature. For the above reason, weighing a hot crucible will not allow the measurement of a constant weight on the balance, since <u>the weight of the object will be constantly changing, which will not allow a constant reading.</u>

3 0
4 years ago
Estimate the surface-to-volume ratio of a C60 fullerene by treating the molecule as a hollow sphere and using 77pm for the atomi
AleksAgata [21]

Answer:

The surface-to-volume ratio of a C-60 fullerene is 3:77.

Explanation:

Surface area of sphere = S=4\pi r^2

Volume of the sphere = V=\frac{4}{3}\pi r^3

where : r  = radius of the sphere

Radius of the C-60 fullerene sphere = r = 77 pm

Surface area of the C-60 fullerene = S=4\pi (77 pm)^2...[1]

Volume area of the C-60 fullerene = V=\frac{4}{3}\pi (77 pm)^3..[2]

Dividing [1] by [2]:

\frac{S}{V}=\frac{4\pi (77 pm)^2}{\frac{4}{3}\pi (77 pm)^3}

=\frac{3}{77}

The surface-to-volume ratio of a C-60 fullerene is 3:77.

7 0
3 years ago
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