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Butoxors [25]
3 years ago
9

-Question 2 please help me! -ASAP-

Chemistry
1 answer:
Reika [66]3 years ago
4 0
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What volume of water has the same mass as 9.0m3 of ethyl alcohol?
Triss [41]
This question requires the knowledge of density. 

The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³

Density = Mass / Volume 

By applying ethyl alcohol,
    789 kg m⁻³ = Mass / 0.9 m³
         Mass     = 710.1 kg
hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.

Then by applying water,
     1000 kg m⁻³ = 710.1 kg / Volume
      Volume        = 0.7101 m³
                          = 0.7 m³
hence the equal water volume is 0.7 m³
8 0
3 years ago
If a tractor trailer and a car are both traveling 50km/h when they hit which will have the greatest change in speed and directio
den301095 [7]
The tractor trailer will push the car when they hit so therefore the car will have to greatest change

4 0
3 years ago
For the reaction C2H5OH + O2 --> 3CO2 + 3H2O
Lelechka [254]
The reaction given above is a combustion reaction. All combustion reactions are exothermic, meaning they give off heat when they react,
8 0
3 years ago
How many ants would 6 giant anteaters need to eat in one year to get the matter and energy they need? Write a simple formula to
prohojiy [21]

Answer:

180,000 ants

Explanation:

For this problem we can create the following simple formula to solve this problem...

f(x) = 6x

where the variable x represents the number of ants that a single Anteater needs to eat per day. After a quick online search we can see that a single Anteater eats roughly 30,000 ants per day. If we use this value and plug it into the simple formula we can get the total number of ants 6 anteaters need to eat to survive.

f(x) = 6 * 30,000

f(x) = 180,000

7 0
3 years ago
A sample of gas in a cylinder as in the example in Part A has an initial volume of 48.0 L , and you have determined that it cont
masya89 [10]

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

\frac{n1}{V1} = \frac{n2}{V2}

we can say that

n2 = n1 \times \frac{V2}{V1}

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

= 1.80 \times \frac{12.0\ L}{48.0\ L}

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

5 0
3 years ago
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