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pogonyaev
3 years ago
14

Can someone please answer my questions it’s urgent!

Chemistry
2 answers:
Luden [163]3 years ago
8 0
Yes, give me the question.
marysya [2.9K]3 years ago
6 0

Answer: Sure.... whats the question

Explanation:

You might be interested in
Arrange steps in order to describe what happens to a gas when it is cooled
AnnZ [28]

A) Particles of gas move slower.

B) Gas changes to liquid.

C) The gas loses thermal energy.

D) Gas particles decrease.

3 0
2 years ago
Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

8 0
3 years ago
A gas sample is collected in a 0.279 L container at 22.7 °C and 0.764 atm. If the sample has a mass of 0.320 g, what is the iden
Sindrei [870]

Answer:

HCl

Explanation:

<em>Choices:</em>

<em>CO: 28.01g/mol</em>

<em>NO₂: 46g/mol</em>

<em>CH₄: 16.04g/mol</em>

<em>HCl: 36.4g/mol</em>

<em>CO₂: 44.01g/mol</em>

<em />

It is possible to identify a substance finding its molar mass (That is, the ratio between its mass in grams and its moles). It is possible to find the moles of the gas using general ideal gas law:

PV = nRT

<em>Where P is pressure of gas 0.764atm; V its volume, 0.279L; n moles; R gas constant: 0.082atmL/molK and T its absolute temperature, 295.85K (22.7°C + 273.15).</em>

Replacing:

PV = nRT

PV / RT = n

0.764atm*0.279L / 0.082atmL/molKₓ295.85K = n

<em>8.786x10⁻³ = moles of the gas</em>

<em />

As the mass of the gas is 0.320g; its molar mass is:

0.320g / 8.786x10⁻³moles = 36.4 g/mol

Based in the group of answer choices, the identity of the gas is:

<h3>HCl</h3>

<em />

4 0
3 years ago
Distinguish between zinc nitrate and lead nitrate ​
Kobotan [32]

Answer:

Zinc nitrate gives white ppt. which dissolves in excess ammonium hydroxide and produce a colorless solution whereas lead nitrate gives a chalky white ppt. of lead hydroxide which doesnot dissolve.

Explanation:

Hope this helps :)

7 0
3 years ago
Which element is nuclear fusion least likely to produce?
adoni [48]

Answer:

silicon

Explanation:

i think

6 0
3 years ago
Read 2 more answers
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