Can someone please answer my questions it’s urgent!
2 answers:
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0.01 m < 0.03 m
< 0.04 m urea
As molal concentration rises, so does freezing point depression. It can be expressed mathematically as ΔTf = Kfm.
<h3>What is Colligative Properties ?</h3>- The concentration of solute particles in a solution, not the composition of the solute, determines a colligative properties .
- Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure reduction are examples of ligand-like properties.
- When less of another non-volatile material is added, the temperature at which a substance freezes decreases, a process known as Freezing-point depression.
- Examples include combining two solids together, such as contaminants in a finely powdered medicine, salt in water, alcohol in water.
- An significant factor in workplace safety is freezing points.
- If a substance is kept below its freezing point, it may become more or less dangerous.
- The freezing point additionally offers a crucial safety standard for evaluating the impacts of worker exposure to cold conditions.
Learn moree about Colligative Properties here:
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Answer:
T₂ = 478.93 K
Explanation:
Given that,
Initial pressure, P₁ = 178 kPa
Initial temperature, T₁ = 37°C = 310 K
Final pressure, P₂ = 275 kPa
We need to find the new temp of the air in the tire, assuming the volume is constant. We know that,
So, the new temperature is equal to 478.93 K.