Answer:
2dQ²/2εA = 2U₀
Explanation:
The energy stored in the ideal parallel plate capacitor U = Q²/2C. For a parallel plate capacitor, C = εA/d where A is the area between the plates and D is the distance between them. So
U = Q²/2C = Q²/2εA/d = dQ²/2εA. At distance d₁ = d, U = U₀,
U₀ = dQ²/2εA,
When d₂ = 2d, U₁ = d₂Q²/2εA = 2dQ²/2εA = 2U₀
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Power = (energy) / (time)
= (1370 joules) / (100 seconds)
= 13.7 joules/second
= 13.7 watts .
That's not an awful lot of power, especially for a strenuous activity like
rock-climbing. Shoot ! Even I could probably perform at that level.
Compare 13.7 watts to the light power coming out of a 20-watt night light.
13.7 watts = 0.018 horsepower. (rounded)
Answer:
Explanation:
Ask a question that can be answered by making observations.