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Verizon [17]
3 years ago
8

Does the electrical conductivity of a wire affect the strength of an electromagnet?

Physics
1 answer:
Mkey [24]3 years ago
4 0
The strength of the electromagnet depends directly on the
current (amps) in the wire that the coil is made out of. 
That current is going to be determined by the voltage of the
battery or power supply that powers the magnet, and by the
resistance of the wire.  So yes, the properties of the wire do
have a direct effect on the strength of the magnet.  If you
tried to make an electromagnet with a coil of wet spaghetti,
it would work, but you would need a humongous power supply
to get any significant strength out of the magnet.
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8 0
3 years ago
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Practice: The speed of sound at sea level is normally about 340 m/s. A car honks its horn as it drives toward an observer. The f
stepan [7]

Answer:

25.5 m/s

Explanation:

The Doppler effect occurs when there is relative motion between a source of a wave and an observer. In such situation, there is a shift in the apparent frequency of the wave perceived by the observer.

The formula that gives the apparent frequency perceived by the observer is:

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the real frequency of the wave

f' is the apparent frequency of the wave

v is the speed of the wave

v_s is the velocity of the source (negative if the source is moving towards the observer, positive otherwise)

v_o is the velocity of the observer (positive if the observer is moving towards the source, negative otherwise)

In this problem:

v = 340 m/s is the speed of sound

f = 800 Hz is the frequency of the horn

f' = 860 Hz is the apparent frequency

v_o=0 (the observer is at rest)

Re-arranging the equation for v_s, we can find the velocity of the horn and the driver:

f'=\frac{v}{v-v_s}f\\(v-v_s)f'=vf\\vf'-v_sf'=vf\\v_s=v\frac{f'-f}{f'}=(340)\frac{860-800}{860}=25.5 m/s

So, 25.5 m/s towards the observer.

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kozerog [31]
The anwser is C it can also be A but C would make the most sense
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4 years ago
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