Answer:
<em><u>Given: </u></em>
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
<em><u>To find:</u></em>
Combined speed of two balls stick together after collision V = ?
<em><u>Solution:</u></em>
<em>According to law of conservation of momentum,</em>
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
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Answer with explanation:
The Normalization Principle states that

Given
Thus solving the integral we get

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

Applying the limits and solving for A we get
![I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7Bk%7D%5B%5Cfrac%7B1%7D%7Be%5E%7Bkx%7D%7D-%5Cfrac%7Bx%7D%7Be%5E%7Bkx%7D%7D%5D_%7B0%7D%5E%7B%2B%5Cinfty%20%7D%5C%5C%5C%5CI%3D-%5Cfrac%7B1%7D%7Bk%7D%5C%5C%5C%5C%5Ctherefore%20A%3D-k)
Answer:
The force required to maintain an object at a constant velocity in free space is equal to Zero.
From the information given,
diameter of ornament = 8
radius = diameter/2 = 8/2
radius of curvature, r = 4
Recall,
focal length, f = radius of curvature/2 = 4/2
f = 2
Recall,
magnification = image d
Answer: 40
Explanation:
I believe this is correct. I did 60/1.5 to get 40/mph