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kiruha [24]
4 years ago
8

Paul graphe% the equatior y=6+x Which point does the graph not pass through? (0,6) (9,15) (6,12) (12,20)

Mathematics
1 answer:
Scilla [17]4 years ago
7 0

You have to substitute the x points for x & the y points for y: (0,6) (9,15) (6,12) (12,20)


y = 6 + x

6 = 6 + 0

6 = 6


y = 6 + x

15 = 6 + 9

15 = 15


y = 6 + x

12 = 6 + 6

12 = 12


y = 6 + x

20 = 6 + 12

20 = 18


The point that does NOT pass through is (12,20).



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Answer:

The Slope Intercept form of the equation through the point (0, -4) and

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Step-by-step explanation:

Here, the given points are A (0,-4) and B(1,0)

Now, slope of the equation with points (a,b) and (c,d) is given as

m = \frac{d - b}{c -a}

So, here the slope of the line AB is given as:

m = \frac{0 - (-4)}{1-0} = \frac{4}{1}  = 4

⇒ m = 4

Now, by POINT SLOPE  form:

The equation with slope m and point  (x0 , y0) is represented as :

(y-y0)  = m (x-x0)

⇒ The equation of AB is of the form with point (1,0) is

y - 0 = 4 (x -1)

or, y = 4 x - 1

Also, the SLOPE INTERCEPT form of an equation is of the form

y = m x + C ;     m = slope and C =  y -intercept

Hence, the slope intercept form of the equation through the point (0, -4) and (1, 0)  is  y = 4 x - 1

4 0
4 years ago
I just need someone to explain how to do it
Mashutka [201]
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hope this helps !
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What multiplies to -75 and adds to 10? <br> thanks
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Step-by-step explanation:

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