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Daniel [21]
4 years ago
11

A flask at room temperature contains exactly equal amounts (in moles) of nitrogen and xenon. Sort the conditions based on the ga

s described. Some may have more than one answer, but noe will have the same answer.
1) Nitrogen has the greater value
2) Xenon has the greater value
3) Both gases have the same value

A. Gas that exerts the greater partial pressure.
B. Gas for which the molecules or atoms have the greatest average velocity
C. Gas that would have a higher rate of effusion through a small hole opened in the flask.
D. Gas for which the molecules or atoms have the greatest average of kinetic energy.
Chemistry
1 answer:
dimulka [17.4K]4 years ago
3 0

Explanation:

Partial pressure is defined as the pressure that is exerted by one of the gases present in a mixture if it occupies the same volume on its own.

As both nitrogen and xenon have occupied same volume. Therefore, both the gases will have same partial pressure.

It is known that average velocity is inversely proportional to molar mass of a gas. Hence, more is the molar mass of a gas lesser will be its average velocity.

Therefore, xenon having high molar mass will have less average velocity and nitrogen gas will have greatest average velocity.

Also, smaller is the molar mass of a gas more will be its rate of effusion because then its molecules will be able to spread readily into the surrounding.

Hence, nitrogen gas will have a higher rate of effusion through a small hole opened in the flask.

Average kinetic energy is represented as follows.

                 K.E = \frac{3}{2}kT

As kinetic energy is directly proportional to temperature. So, with increase in temperature there will occur an increase in kinetic energy of the molecules.

Hence, average of kinetic energy will be same for both the gases.

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The type of memory in which an individual has problem to remember a planned set of actions. He or she can remember or recall it only after some period of time may be in future and not at that time where those actions needs to be performed. These type of memory problem can range from a simple situation like the tasks that are to be done in common, simple and daily basis to serious issue.

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3 years ago
What is the empirical formula and empirical formula mass for the following compound? C3H6O3?
babunello [35]
Answer: C3H6O3 > CH2O
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An insulated cup contains 66.0g of water at 22.00oC. A 28.50g sample of metal at 95.25oC is added. The final temperature of the
Vsevolod [243]

Answer:

Specific heat of metal of the metal is 0.8394J/g°C

Explanation:

The heat the water gain is the same losing for the metal. The equation is:

m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)

<em>Where m is mass: 66.0g water and 28.5g Metal</em>

<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>

<em>And S is specific heat of water (4.184J/g°C) and the metal</em>

<em />

Replacing:

28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C

S(Metal) = 0.8394J/g°C

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3 years ago
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8 0
3 years ago
2C3H6O + 8O2 --&gt; 6CO2 + 6H2O
grigory [225]

Answer: 0.45 moles of H_2O will be produced from 0.15 moles of propanol.

Explanation:

The balanced chemical reaction is:

2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O

C_3H_6O is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

According to stoichiometry :

2 moles of C_3H_6Oproduces = 6 moles of H_2O

Thus 0.15 moles of V will produce=\frac{6}{2}\times 0.15=0.45moles  of H_2O

Thus 0.45 moles of H_2O will be produced from 0.15 moles of propanol.

7 0
3 years ago
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