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bulgar [2K]
3 years ago
7

What is the mass of 1.20 x 10^25 atoms of He

Chemistry
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

79.7 g He

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

1.20 × 10²⁵ atoms He

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of He - 4.00 g/mol

<u>Step 3: Convert</u>

<u />1.20 \cdot 10^{25} \ atoms \ He(\frac{1 \ mol \ He}{6.022 \cdot 10^{23} \ atoms \ He} )(\frac{4.00 \ g \ He}{1 \ mol \ He} ) = 79.7077 g He

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

79.7077 g He ≈ 79.7 g He

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Answer:

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Explanation:

Boiling point depends on different intermolecular force such as molecular wight, dipole-dipole attraction force, hydrogen bonding, ionic attraction force.

Homonuclear diatomic molecules are covalent non-polar molecules and thereby free from dipole-dipole attraction force, hydrogen bonding and ionic interaction forces.

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We know, higher the molecular weight of a molecule, higher will be its boiling point. This phenomenon can be realized in terms of increasing london dispersion force with increase in molecular weight.

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At which temperature do the molecules of an ideal gas have 3 times the kinetic energy they have at 32of?
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Answer:

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Explanation:

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Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

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  • Second, convert 0°C to kelvin:

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