It was in Texas on September 8, 1900.
Answer:
V_{average} =
, V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) = ![\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7BV%3DV_o%20%5C%20%5C%20%5C%20%20t%3C%20%20%5Ctau%20%2F2%7D%20%5Catop%20%7BV%3D0%20%5C%20%5C%20%20%5C%20%5C%20%20t%3E%20%5Ctau%20%2F2%20%7D%20%20%20%7D%20%5Cright.)
to substitute in the equation let us separate the into two pairs
V_average = ![\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B1%2F2%7D_0%20%7BV_o%7D%20%5C%2C%20dt%20%2B%20%5Cint%5Climits%5E1_%7B1%2F2%7D%20%7B0%7D%20%5C%2C%20dt)
V_average = ![V_o \ \int\limits^{1/2}_0 {} \, dt](https://tex.z-dn.net/?f=V_o%20%5C%20%5Cint%5Climits%5E%7B1%2F2%7D_0%20%7B%7D%20%5C%2C%20dt)
V_{average} = ![\frac{1}{2} V_o](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%20V_o)
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V
Answer:
Explanation:
a. The source of centripetal force on the car is (3) the static friction force.
b. ac = v²/R = (20²)/50 = 8 m/s²
c. Fc = m(ac) = 1500(8) = 12 kN
d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82
Answer:
F_g = 372.78 N
Explanation:
Formula for force of gravity is;
F_g = mg
Where;
m is mass
g is acceleration due to gravity
We are given;
Mass = 38 kg
Acceleration due to gravity has a constant value of 9.81 m/s²
Thus;
F_g = 38 × 9.81
F_g = 372.78 N