All categories

4 years ago

What is the mass of a liquid having a density of 1.50 g/ml and a volume of 3.5 liters?

Physics

1 answer:

PIT_PIT [208]4 years ago

6 0

We know the formula for density = Mass/ volume

So Mass, M = Volume * Density

Volume = 3.5 L= 0.0035 $m^3$

Density = 1.50 g/ml = 1500 $kg/m^3$

Mass, M = 0.0035*1500 = 5.25 kg

So mass of liquid having density 1.50 g/ml and volume 3.5 liters is 5.25 kg.

You might be interested in

A shear force of 400 N is applied to one face of an aluminum cube with sides of 30 cm. What is the resulting relative displaceme

shtirl [24]

Answer:

5.3 × 10^(-8) m

Explanation:

We are given;

Shear force; F = 400 N

Length of cube; L_o = 30 cm = 0.3 m

Shear modulus; S = 2.5 × 10^(10) N/m²

Now,the resulting relative displacement can be gotten from the formula;

F = A × S × Δx/L_o

Where Δx is resulting relative displacement

A is area.

Area of cube = (L_o)² = 0.3² = 0.09

Thus, making Δx the subject, we have;

Δx = (F × L_o)/(A × S)

Plugging in the relevant values;

Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))

Δx = 5.3 × 10^(-8) m

6 0

3 years ago

A roller-coaster car has a mass of 1040 kg when fully loaded with passengers. As the car passes over the top of a circular hill

rusak2 [61]

Answer:

a.6373.5 N

b.-3837.6 N

Explanation:

Mass of roller coaster=m=1040 kg

Radius=r=24 ,

a. $v=9.4m/s$

Normal force= $F_N$

According to question

$mg-F_N=\frac{mv^2}{r}$

Where $g=9.81 m/s^2$

Substitute the values

$1040\times 9.81-F_N=\frac{1040\times (9.4)^2}{24}$

$10202.4-F_N=3828.9$

$F_N=10202.4-3828.9=6373.5 N$

b. $v=18m/s$

$g=9.81 m/s^2$

$1040\times 9.81-F_N=\frac{1040\times (18)^2}{24}$

$10202.4-F_N=14040$

$F_N=10202.4-14040=-3837.6 N$

8 0

4 years ago

Which example best

Snezhnost [94]

Answer:

Explanation:

paddling a canoe to make the boat move

7 0

3 years ago

A force of magnitude 33.73 lb directed toward the right is exerted on an object. What other force must be applied to the object

vova2212 [387]

Answer:

33.73 lb to the left

Explanation:

You need to exert a force with the same magnitude, but opposite direction. You can visualize it in this way: When you push an object, the object will follow your path, but if there is another person opposing the force you are exerting, the object will just not move. If the force that the other person exerts were higher, then the object would move in the opposite direction. So, you need them to have the same magnitude.

7 0

3 years ago

Describe a ball's motion as it rolls up a slanted

emmasim [6.3K]

The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

The given parameters;

initial velocity of the ball, u = 1.25 m/s
time of motion of the ball, t = 4.22 s

As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

$a = \frac{v_f -v_0}{t} \\\\$

<em>at the highest point on the incline plane, the final velocity </em> $v_f$ <em> is zero</em>

$a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2$

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

Learn more here:brainly.com/question/23860763

4 0

3 years ago