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Elodia [21]
3 years ago
14

What would happen if an atom of fluorine (F) came into contact with an atom of neon (Ne)?

Chemistry
1 answer:
juin [17]3 years ago
7 0
A. nothing neon is a noble gas, meaning that it dosnt react with anything
You might be interested in
Give two reasons why a luminous flame is not used for heating purposes. (2mks) a​
Natali [406]

Answer:

The Two reasons are :-

1. Combustion efficiency

2. Standardization of test conditions as non-luminous flame.

Explanation:

A luminous flame isn't suitable for heating as it gives out soot (A black powdery or flaky substance consisting largely of amorphous carbon, produced by the incomplete burning of organic matter)

8 0
2 years ago
Determine the number of molecules in 3.79 kilograms of the fictional compound Cs7(Cr5O3)4. Include the units, but do not write t
Karo-lina-s [1.5K]

Answer:

1.0555 * 10^24 molecules

Explanation:

Number of molecules = ?

Mass = 3.79  Kg = 3790 g

Molar mass of Cs7(Cr5O3)4 = 2162.25 g/mol

Number of moles = Mass / Molar mass

Number of moles = 3790 g / 2162.25 g/mol

Number of moles = 1.7528 mol

1 mol = 6.022 * 10^23 molecules

1.7528 mol = x

solving for x;

x = 6.022 * 10^23 *  1.7528

x = 1.0555 * 10^24 molecules

7 0
2 years ago
Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below. A pur
Julli [10]

Answer:

dude that doesnt maek sense

Explanation:

6 0
2 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!! Its due tonight at 12:00
Dmitry [639]

Answer:

c

Explanation:

we have only distance vs time graph so c is the right answer that cart is moving with constant speed of 0.5m/s

confirmed

first calculate distance which is from 2 to 5.5

5.5-2=3.5

apply the formula of velocity

v=s/t

v=3.5/7=0.5

8 0
2 years ago
Read 2 more answers
Potassium iodide reacts with lead(II) nitrate in this precipitation reaction: 2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s) Wha
andrew11 [14]

Answer:

a. 174 mL

Explanation:

Let's consider the following reaction.

2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)

We have 155.0 mL of a 0.112 M lead(II) nitrate solution. The moles of Pb(NO₃)₂ are:

0.1550 L × 0.112 mol/L = 0.0174 mol

The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:

2 × 0.0174 mol = 0.0348 mol

The volume of a 0.200 M KI solution that contains 0.0348 moles is:

0.0348 mol × (1 L / 0.200 mol) = 0.174 L = 174 mL

5 0
2 years ago
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