Question

How many mol of sodium corresponds to 1.0 x 10^15 atoms of sodium?

Answer 1

Answer:

The moles of sodium are $1.6606\times 10^{-9} moles$.

Explanation:

Moles of sodium = n

Number of atoms of sodium , N = $1.0\times 10^{15}$

$N=n\times N_A$

Where ,$N_A= 6.022\time 10^{23} mol^{-1}$ atoms/ molecules (Avogadro number)

$n=\frac{N}{N_A}=\frac{1.0\times 10^{15}}{6.022\time 10^{23} mol^{-1}}$

n = $1.6606\times 10^{-9} moles$

The moles of sodium are $1.6606\times 10^{-9} moles$.

Answer 2

The Avogadro number represents the number of units in one mole of a chemical substance.
So to find the mole number of a chemical element, you divide its atom number of the Avogadro number which Na = 6.02*10^23 approx.
So n=N/Na (n=mole number, N=number of atoms, Na=Avogadro number)
n=1.0*10^15/6.02*10^23
n=1.6 * 10^-9

So 1.0*10^15 atoms of Sodium represent 1.6*10^-9 mol.

Hope this Helps! :)