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3 years ago

What is the midpoint of the line segment

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

5 0

Answer:

The answer to your question is (-1, -1)

Step-by-step explanation:

Data

A (1, -6)

B (-3, 4)

Formula

Xm = $\frac{x1 + x2}{2}$

Ym = $\frac{y1 + y2}{2}$

Process

1.- Substitute the values in the formula

x1 = 1 x2 = -3

Xm = $\frac{1 - 3}{2} = \frac{-2}{2} = -1$

y1 = -6 y2 = 4

Ym = $\frac{-6 + 4}{2} = \frac{-2}{2} = -1$

2.- The midpoint is (-1, -1)

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Perimeter question math

Aneli [31]

Perimeter is the sum of all sides in the figure. Here, all six sides are equal in length so it would be:

p = 6 * side
p = 6 * 3.9
p = 23.4 cm

In short, Your Answer would be: 23.4 cm

Hope this helps!

5 0

3 years ago

Read 2 more answers

Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of

satela [25.4K]

Answer:

The position P is:

$P = 87\^x + 75\^y$ ft Remember that the position is a vector. Observe the attached image

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity $s_0$ is:

$y(t) = y_0 + s_0t -16t ^ 2$

Where $y_0$ is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

$s_0 = 82sin(58\°)$ ft/sec

$s_0 = 69.54$ ft/sec

Thus

$y(t) = 69.54t -16t ^ 2$

The height after 2 sec is:

$y(2) = 69.54 (2) -16 (2) ^ 2$

$y(2) = 75\ ft$

Then the equation that describes the horizontal position of the ball is

$X(t) = X_0 + s_0t$

Where

$X_ 0 = 0$ for this case

$s_0 = 82cos(58\°)$ ft / sec

$s_0 = 43.45$ ft/sec

$X(t) = 43.45t$

After 2 seconds the horizontal distance reached by the ball is:

$X (2) = 43.45(2)\\\\X (2) = 87\ ft$

Finally the vector position P is:

$P = 87\^x + 75\^y$ ft

6 0

3 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

3 years ago

Amanda leaned a 15-foot ladder against the top of her house so she could get on the roof, which is 12 feet from the ground.

valentinak56 [21]

If you're trying to find the missing side of the "triangle" (the distance from the house to where the ladder touches the ground), you would use the pythagorean theorem, a²+b²=c². (c is always hypotenuse)

a²+b²=c²

12²+b²=15²

144+b²=225

b²=81

√b²=√81

b=9

8 0

3 years ago

3 Solve for x. 1 14 10 56 40 " 14 56

Nesterboy [21]

Answer:

Step-by-step explanation:

the shapes are similar which means the sides are proportional, you can set up a ratio using the sides as 10/40 = 3/x

solving that gives you x =12

5 0

2 years ago