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3 years ago

What is the midpoint of the line segment

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

5 0

Answer:

The answer to your question is (-1, -1)

Step-by-step explanation:

Data

A (1, -6)

B (-3, 4)

Formula

Xm = $\frac{x1 + x2}{2}$

Ym = $\frac{y1 + y2}{2}$

Process

1.- Substitute the values in the formula

x1 = 1 x2 = -3

Xm = $\frac{1 - 3}{2} = \frac{-2}{2} = -1$

y1 = -6 y2 = 4

Ym = $\frac{-6 + 4}{2} = \frac{-2}{2} = -1$

2.- The midpoint is (-1, -1)

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Anna11 [10]

I'll assume you're supposed to compute the line integral of $\nabla f$ over the given path $C$ . By the fundamental theorem of calculus,

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so evaluating the integral is as simple as evaluting $f$ at the endpoints of $C$ . But first we need to determine $f$ given its gradient.

We have

$\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)$

Differentiating with respect to $y$ gives

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4 years ago

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andrew-mc [135]

Answer: 64°

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3 years ago

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Dahasolnce [82]

Answer:

24 x y

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Simplify the following:

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Hint: | Multiply 3 and 4 together.

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3 years ago

If we inspect photocopy paper by randomly drawing 5 sheets without replacement from every pack of 500, what is the probability o

earnstyle [38]

Answer:

98.01% probability of getting 5 clean sheets

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, the order that the sheets are chosen is not important, so we use the combinations formula to solve this problem.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

0.4% of the sheets contain spots

Of 500, that is 0.004*500 = 2.

What is the probability of getting 5 clean sheets although 0.4% of the sheets contain spots?

Desired outcomes

2 are defective, so 5 sheets from a set of 500 - 2 = 498.

$D = C_{498,5} = \frac{498!}{5!493!} = 250160254344$

Total outcomes

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$T = C_{500,5} = \frac{500!}{5!495!} = 255244687600$

Probability:

$P = \frac{D}{T} = \frac{250160254344}{255244687600} = 0.9801$

98.01% probability of getting 5 clean sheets

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4 years ago