Answer:
The extension of the wire is 0.362 mm.
Explanation:
Given;
mass of the object, m = 4.0 kg
length of the aluminum wire, L = 2.0 m
diameter of the wire, d = 2.0 mm
radius of the wire, r = d/2 = 1.0 mm = 0.001 m
The area of the wire is given by;
A = πr²
A = π(0.001)² = 3.142 x 10⁻⁶ m²
The downward force of the object on the wire is given by;
F = mg
F = 4 x 9.8 = 39.2 N
The Young's modulus of aluminum is given by;

Where;
Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

Therefore, the extension of the wire is 0.362 mm.
Answer:
A chemical change produces a new substance, while a physical change does not
Answer:
1.07 nT
Explanation:
We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.
So, B = E/c
Substituting E and c into B, we have
B = E/c
= 0.32 V/m ÷ 3 × 10⁸ m/s
= 0.1067 × 10⁻⁸ T
= 1.067 × 10⁻⁹ T
= 1.067 nT
≅ 1.07 nT
Answer:
Explanation:
A stretching routine should target most of the main muscles in the body and at least one stretching exercise per section of the body. Also in a work environment since individual's sizes, ages, and cultures vary you should design a routine that is for beginners and very easy and effective. Regardless, each individual should be able to move at their own pace and push as far as they are physically able. One such routine would be the one in the attached picture below which targets all major areas, is easy and effective. It starts at the neck muscles and works its way down the arms, back, and legs.
Answer:
C. resonating
an object being forced to vibrate at its natural frequency creates resonance