Answer:
e. weight = mass x gravitational field strength
Answer:
T = 5.36 s
Explanation:
given,
depth of the mine shaft = 122.5 m
speed of the sound = 340 m/s
time taken = ?
time taken by the stone to reach at the bottom
using equation of motion
![s = u t + \dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=s%20%3D%20u%20t%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
initial speed , u = 0 m/s
![t = \sqrt{\dfrac{2s}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cdfrac%7B2s%7D%7Bg%7D%7D)
![t = \sqrt{\dfrac{2\times 122.5}{9.8}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%20122.5%7D%7B9.8%7D%7D)
t = 5 s
time taken by the sound to travel
d =v x t
![t = \dfrac{d}{v}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7Bd%7D%7Bv%7D)
![t = \dfrac{122.5}{340}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7B122.5%7D%7B340%7D)
t = 0.36 s
total time taken for the sound to reach carol after dropping the stone
T = 5 + 0.36
T = 5.36 s
Can you translate to english ?
In this exercise we have to know the definition of energy to understand what is transferred to a body, like this:
Work
<h2>What is energy?</h2>
Despite being used in many different contexts, the scientific use of the word energy has a well-defined and precise meaning: Innate potential to perform work or perform an action. Anything that is working, moving another object, or heating it up, for example, is expending (transferring) energy.
With this definition we can say that the only alternative that responds to this is work.
See more about energy at brainly.com/question/1932868
Explanation:
Speed of Bob, v = 0.967 c
At the exact instant he passes Alice, she fires a very short laser pulse in the same direction Bob is moving.
(a) We need to find the distance measured by Alice between Bob and the laser pulse. It is given by :
![d=ct-vt](https://tex.z-dn.net/?f=d%3Dct-vt)
![d=t(c-v)](https://tex.z-dn.net/?f=d%3Dt%28c-v%29)
![d=5.59\times (c-0.967c)](https://tex.z-dn.net/?f=d%3D5.59%5Ctimes%20%28c-0.967c%29)
![d=5.53\times 10^7\ meters](https://tex.z-dn.net/?f=d%3D5.53%5Ctimes%2010%5E7%5C%20meters)
(b) Distance measured by Bob between himself and the laser pulse is given by :
![d_B=ct](https://tex.z-dn.net/?f=d_B%3Dct)
![d_B=3\times 10^8\times 5.59](https://tex.z-dn.net/?f=d_B%3D3%5Ctimes%2010%5E8%5Ctimes%205.59)
![d_B=6.67\times 10^9\ meters](https://tex.z-dn.net/?f=d_B%3D6.67%5Ctimes%2010%5E9%5C%20meters)
Hence, this is the required solution.