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3 years ago

Asap? This heating curve is produced when a certain substance is heated.

Physics

2 answers:

MaRussiya [10]3 years ago

5 0

Answer: the particles are more orderly in region 1

Explanation: region 1 is when the substance is a solid and as it is heated the particles move further apart and have more kinetic energy.

Novay_Z [31]3 years ago

3 0

Answer:

The particles are more orderly in region 1.

Explanation:

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A plane starting from rest (vo = 0 m/s) when t0 = 0s. The plane accelerates down the runway, and at 29 seconds, its velocity is

IrinaK [193]

Answer:

Acceleration, $a=2.48\ m/s^2$

Explanation:

Given that,

The plane is at rest initially, u = 0

Final speed of the plane, v = 72.2 m/s

Time, t = 29 s

We need to find the average acceleration for the plane. It can be calculated as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{72.2}{29}$

$a=2.48\ m/s^2$

So, the average acceleration for the plane is $2.48\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago

A 1300 kg car traveling at 35 mph rear-ends a 1000 kg car traveling 25 mph. Just after the collision (but before the driver’s sl

guajiro [1.7K]

Answer

given,

before collision

mass of car A = m_a = 1300 kg

velocity of car A = v_a = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

$P_1 = m_av_a + m_b v_b$

$P_1 = 1300 \times 35+ 1000 \times 25$

$P_1 =70500 Kg.m/s$

final momentum

$P_2 = m_aV_a + m_b V_b$

$P_2 = 1300 \times 30+ 1000 \times 31.5$

$P_2 =70500 Kg.m/s$

here initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

6 0

3 years ago

Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon

Katarina [22]

Answer:

upward force acting = 261.6 N

Explanation:

given,

mass of gibbon = 9.4 kg

arm length = 0.6 m

speed of the swing

net force must provide

$F_{branch} + F_{gravity}=F_{centripetal}$

force of gravity = - mg

$F_{branch}=F_{centripetal}-F_{gravity}$

= $\dfrac{mv^2}{r} + mg$

= $m(\dfrac{3.4^2}{0.6} +9.8)$

=9 x 29.067

= 261.6 N

upward force acting = 261.6 N

7 0

3 years ago

Equation for pressure at a depth H inside a fluid PLSS URGENTT

Blababa [14]

Answer:

We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.

4 0

3 years ago

Do these four animals have invertebrates?

ira [324]

The worm is the invertebrate. All the other animals are vertebrates.

5 0

3 years ago