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3 years ago

15

Which term describes the transfer of thermal energy from one object to another because of a difference in temperature? 1.energy

2.friction 3.heat 4.work

1 answer:

gregori [183]3 years ago

6 0

The answer is 3.heat

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A force of 40 N is required to hold a spring that has been stretched from its natural length of 10 cm to a length of 15 cm. How

Sati [7]

0.36 J of work is done in stretching the spring from 15 cm to 18 cm.

To find the correct answer, we need to know about the work done to strech a string.

<h3>What is the work required to strech a string?</h3>

Mathematically, the work done to strech a string is given as 1/2 ×K×x².
K is the spring constant.

<h3>What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?</h3>

The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length.
Then K = Force / x.
Here x = 15 - 10 = 5 cm = 0.05 m
K = 40/0.05 = 800N/m.

<h3>What will be the work required to strech that spring from 15 cm to 18 cm?</h3>

Work done = 1/2×k×x²
Here x= 18-15=3cm or 0.03 m
So, W= 1/2×800×0.03² = 0.36 J.

Thus, we can conclude that the work done is 0.36 J.

Learn more about the spring force here:

brainly.com/question/14970750

#SPJ4

6 0

2 years ago

A rocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. It moves for 7 s along its initial

vagabundo [1.1K]

Answer:

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

$a=19 \frac{m}{s^{2} } \\voy=vo*sin(\alpha )\\voy=90*sin(39 )\\y_{o}=0m\\y_{f}=y_{o}+v_{oy}*t+\frac{1}{2}*a*t^{2}\\y_{f}=90*sin(39)*7s+\frac{1}{2}*19\frac{m}{s^{2} }*(7)^{2}\\y_{f}=861.97m$

Now the motion the rocket moves as a projectile so:

$v_{fy}=v_{iy}+a*t\\v_{fy}=90+9.8*7\\v_{fy}=158.6 sin(39)$

Now the final velocity is the initial in the second one

$v_{fy}^{2}=v_{fi}^{2}+2*a*yf \\\\a=g\\$

The maximum altitude Vf=0

$0=v_{fi}^{2}+2*a*yf \\\\yf=\frac{(158.6 sin(39))^{2} }{2*9.8\frac{m}{s^{2} } } \\yf=508.26m$

So total altitude is both altitude of the motion so:

$Y=508.2m+861.97m\\Y=1370.23m$

6 0

3 years ago

What is the difference between electric field and electrostatic field?

valentina_108 [34]

Semantically? An electric field does not have to be static while in electrostatics it's generally assumed that the electric field does not change or only changes so slowly that its rate of change doesn't matter. That's very different in electrodynamics where electric and magnetic field changes are always coupled.

7 0

4 years ago

Read 2 more answers

A 1610 kg car is traveling east at 22. m/s and a 3100. kg minivan traveling west at a speed of 11.0 m/s

Schach [20]

Answer:

Im pretty sure its 11 m/s east because it is 22 m/s hitting 11 m/s and the force is harder hitting

Explanation:

im not 100% sure becasue i did this stuff a while ago

8 0

3 years ago

A graduated cylinder contains 63.0 mL of water. A piece of gold, which has a density of 19.3 g/ cm3, is added to the water and t

icang [17]

Answer:

29.0 g

Explanation:

The mass of the piece of gold is given by:

m = dV

where

m is the mass

d is the density

V is the volume of the piece of gold

The density of gold is

d = 19.3 g/cm^3

while the volume of the sample is equal to the volume of displaced water, so

V = 64.5 mL - 63.0 mL = 1.5 mL

And since

1 mL = 1 cm^3

the volume is

V = 1.5 cm^3

So the mass of the piece of gold is:

m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g

7 0

3 years ago