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Hatshy [7]
3 years ago
7

A 2.00x10^6 hertz radio signal is sent a distance of 7.30x10^10 meters from earth to a spaceship orbiting Mars. How much time do

es it take for the radio signal to travel from earth to the spaceship
Physics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

It takes  2.43\times 10^2  for the radio signal to travel from earth to the spaceship.

Explanation:

Given:

The frequency of the radio signal =  2.00 \times 10^6 hertz

Distance =7.30\times 10^10 meters

To Find:

The time taken for the radio signal to travel from the earth to the spaceship= ?

Solution:

we know that the time taken can be found by dividing the distance travelled by the speed at which the signal travels

So

Time = \frac{Distance}{Speed}

Here the speed of the radio signal is equal the the speed of light

Now substituting the values,

Time taken is

=>Time = \frac{7.30\times 10^10}{3 \times 10^8}

=>Time = 2.43\times 10^{10-8}

=>Time = 2.43\times 10^2

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How did the ideas of einstein and freud contribute to a sense of uncertainty?
Ipatiy [6.2K]
Einstein's Theory of Relativity was a theory which carried about hesitation in Newton's gravity which was measured as an important part of science. Which brings one to query what we detect as being factual. 
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6 0
3 years ago
Which of the balls will exert the smallest force on object A?Why
olganol [36]
The 1kg ball would exert the smallest force.

As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.

When the mass is lighter (1kg):

Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N

Compared to when the mass is heavier (10kg)

Force = mass x gravity
Force = 10 x 9.8
Force = 98N

Where this proves that the lighter the mass, the smaller the force exerted.
6 0
3 years ago
A 7750 kg space probe, moving nose-first toward Jupiter at 179 m/s relative to the Sun, fires its rocket engine, ejecting 72.0 k
Reika [66]

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute

7750(179)+72(230) = (7750+72)v

1,387,250+16560 = 7822v

1,403,810 = 7822v

v = 1,403,810/7822

v= 179.47m/s

Hence the final velocity of the probe is 179.47m/s

7 0
3 years ago
If e is the electric field near an infinite sheet of charge and E is electric field between two similarly charged parallel plate
PolarNik [594]

Answer:

* the two plates of the same sign  E = 0

* the two plates of different sign    E/e = 2

Explanation:

In this exercise, the relationship between the field created by a plate and two infinite plates is asked.

The electric field created by each plate has the value of "e", which is related to the charge on the electric plate.

                 e = \frac{ \sigma }{2 \epsilon_o}

If the plate is negative the electric field is directed towards the plate and if the plate is positive the electric field is directed out of the plate.

The test charge is always positive.

When we have two plates, we have several possibilities

* the two plates of the same sign

therefore the resulting electric field on the test charge is

              E_total = e - e

              E = 0

* the two plates of different sign

              E_total = e + e

               E = 2 e

the relationship between the two fields is

             E/e = 2

6 0
3 years ago
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