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Free_Kalibri [48]
3 years ago
6

During the processes of erosion and deposition, sediments that are the ________ in size will be carried the greatest distances b

efore being deposited
(There's no choices it's just fill in the blank)
Also
Most _______ rocks form under conditions found a few kilometers under earths surface
(No choices,fill in the blank)
Chemistry
2 answers:
Mila [183]3 years ago
4 0
<span>During the processes of erosion and deposition, sediments that are the smaller </span>in size will be carried the greatest distances before being deposited. Most metamorphic rocks form under conditions found a few kilometers under earths surface
Ahat [919]3 years ago
3 0

The full sentences are given below:

1. During the process of erosion and deposition, sediments that are the SMALLEST in size will be carried the greatest distance before being deposited.

Erosion and deposition are the methods by which sand and rock particles are moved from one place to another. The erosion can be caused by water or wind. Water and wind have the capacity to transport particle from one location and deposit them in another location. How far the erosion is able to move the particles depend on the weight of the particles. It is easier for erosion to carry small particles over a long distance than for it to carry large particles over the same distance.

2. Most METAMORPHIC rocks form under conditions found a few kilometer under the earth surface.

Metamorphic rocks generally are formed from existing rocks. The existing rocks are usually subjected to heat and pressure, which cause radical changes in the chemical and physical properties of the rock. Metamorphic rocks can be formed underneath the earth surface if they are subjected to high temperature and pressure by the rock layers above them.

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a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu
Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

3 0
3 years ago
Living things respire to stay alive. In the mitochondria, sugar is combined with oxygen to produce energy, water and carbon diox
olya-2409 [2.1K]

Answer:

C6H12O6 + 6O2 → 6CO2 + 6H2O

Explanation:

Cellular respiration occurs in the mitochondria of cells. It is a process in which  sugar is combined with oxygen to produce energy, water and carbon dioxide. This is the major process by which energy is released in living organisms.

Aerobic respiration involves a series of chemical reactions.  These reactions commence with sugar and oxygen then it produces  carbon dioxide and water according to the reaction equation; C6H12O6 + 6O2 → 6CO2 + 6H2O.

8 0
2 years ago
Read 2 more answers
Looking at the following equation, what coefficient should be placed in front of the H2? Fe + H2SO4 --&gt; Fe2(SO4)3 + H2
Hatshy [7]

Answer:

3 (three)

Explanation:

2 Fe + 3H2SO4 = Fe2(SO4)3 + 3 H2 (basically just balance both sides)

6 0
3 years ago
Hat volume of a 0.540 M NaOH solution contains 12.5 g NaOH
amid [387]

Answer:

At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.

Explanation:

Given data:

At volume = ?

Mass of NaOH = 12.5 g

Molarity of solution = 0.540 M

Solution:

First of all we will calculate the number of moles of sodium hydroxide.

Number of moles = mass/molar mass

Number of moles = 12.5 g / 40 g/mol

Number of moles = 0.3125 mol

Volume of NaOH:

Molarity = number of moles / volume in L

Now we will put the values.

0.540 M = 0.3125 mol / volume in L

volume in L = 0.3125 mol / 0.540 mol/L

volume in L = 0.58 L

5 0
3 years ago
You complete a chemical reaction and recover 79 grams of product. However, you calculate you should have recovered 104 grams of
spin [16.1K]
Percent yield is calculated using:
percent \: yield =  \frac{actual \: yield}{theoretical \: yield}   \times 100\%

Your actual yield is how much you actually had at the end of the experiment = 79g.

Your theoretical yield is how much you calculated you should have gotten in an ideal, perfect experiment = 104g.

So put those values into the equation:
percent \: yield =  \frac{79}{104}  \times 100\% = 76\%

5 0
3 years ago
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