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4 years ago

What type of intermolecular force accounts for the following differences in each case?

1 answer:

5 0

This will be highly depended on the case,
for example, when hydrogen attached to electromotive atom, we call it hydrogen bonding.
if the electrons in two atoms make them temporary dipole, we called it london dispersion forces, etc

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The end point of a titration was reached after 22 ml of 0.050 m disodium edta titrant was dispensed into a solution containing t

ale4655 [162]

The moles of disodium edta used is calculated using the below formula

moles =molarity x volume in liters

molarity=0.050m
volume in liters = 22/1000=0.022 L

moles is therefore= 0.022 x0.050 =1.1 x10^-3 moles of disodium edta

4 0

4 years ago

Read 2 more answers

100. mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution

PolarNik [594]

Answer: The molar mass of the unknown protein is 6387.9 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 0.0766 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of protein = 100. mg = 0.100 g (Conversion factor: 1 g = 1000 mg)

Molar mass of protein = ?

Volume of solution = 5.00 mL

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$0.0766atm=1\times \frac{0.100\times 1000}{\text{Molar mass of protein}\times 5}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\\pi=\frac{1\times 0.100\times 1000\times 0.0821\times 298}{0.0766\times 5}=6387.9g/mol$

Hence, the molar mass of the unknown protein is 6387.9 g/mol

5 0

4 years ago

HELP best answer = brainiest !

Ket [755]

Cell wall is only plant I believe

4 0

4 years ago

Organisms that have the ability to use an atmospheric gas to produce an organic nutrients are known as?

Andrew [12]

Its an autotrophs because they use carbon monoxide

4 0

4 years ago

If 5400. Joules of energy were supplied to 4.5 grams of ice at -10 degree Celsius, how many grams of what phases would you have?

devlian [24]

The answers to you questions are 3,66 g of liquid water and 0,84 g of vapor.
Solution:1) Q₁ = mxCxΔT = 4,5 g x 2,108 J/°C x g x 10°C.
= 97,86 J heat required to warm the ice to 0°C.

2) = 4,5 g x 334 J/g. = 1503 J heat required to melt the ice to water at 0°C.

3) = 4,5 g x 4,184 J/°C x g x 100°C
= 1882,28 J heat required to warm the water from 0°C to 100°C. = 5400 J - 3483,14 J = 1916,86 J heat left to vaporize the water.

mass of the vapor= 1916,86 J ÷ 2257 J/g
= 0,84 g.

3 0

3 years ago

Read 2 more answers