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AnnyKZ [126]
4 years ago
15

Given that log N = -a, derive an expression for N the antilogarithm in scientific location.

Chemistry
1 answer:
SashulF [63]4 years ago
5 0
Some people, by convention, use log to mean base 10. If that is the case then N = 10^-a

If we do not know the base, we can call it b and thus
N = b^-a
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solmaris [256]
<span>(0.1875 moles)(98.004 g/mole) = 18.37575 g </span>
<span>In correct number of significant figures: 18.4 </span>
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3 years ago
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Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.
Sever21 [200]

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

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3 years ago
Describe melting of a solid
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3 0
4 years ago
After substantial heating, 6.25 g of iron produced 18.00 g of a compound with chlorine. The empirical formula is:
babunello [35]

Answer:

Option A. FeCl3

Explanation:

The following data were obtained from the question:

Mass of iron (Fe) = 6.25g

Mass of the compound formed = 18g

From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow

Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.

Mass of chlorine (Cl) = 18 – 6.25

Mass of chlorine (Cl) = 11.75g

The compound therefore contains:

Iron (Fe) = 6.25g

Chlorine (Cl) = 11.75g

The empirical formula for the compound can be obtained by doing the following:

Step 1:

Divide by their molar mass

Fe = 6.25/56 = 0.112

Cl = 11.75/35.5 = 0.331

Step 2:

Divide by the smallest

Fe = 0.112/0.112 = 1

Cl = 0.331/0.112 = 3

The empirical formula for the compound is FeCl3

3 0
3 years ago
How many moles of KCL is in a 3M solution of KCL
netineya [11]

Answer:

223.6539

Explanation:

1 mole is equal to 1 moles KCl, or 74.5513 grams

4 0
4 years ago
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