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velikii [3]
2 years ago
12

Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.

Chemistry
1 answer:
Sever21 [200]2 years ago
5 0

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

Spectators ions are ions present on both sides of the ionic equation by the same quantity but do not take part in the net reaction.

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What type of reaction is Cl2+2NaBr=NaCl+Br2
Gnoma [55]

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5 0
2 years ago
MM H2O2 = 34.02 g/mol MM H2O = 18.02 g/mol MM O2 = 32 g/mol
Kaylis [27]

  The grams   of oxygen that  are   produced  is  228.8 grams


  <em>calculation</em>

2H₂O₂ → 2H₂O +O₂

Step 1:  use  the  mole ratio to determine the moles of O₂

from equation above H₂O₂:O₂  is   2:1

therefore the  moles of O₂  = 14.3 moles ×1/2 = 7.15   moles

Step 2:  find  mass   of O₂

mass = moles ×  molar mass

= 7.15 moles × 32 g/mol =228.8 g

3 0
3 years ago
What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
adell [148]

Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

⇒ with n = the number of moles O2 = 0.09975 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

⇒ with p = 0.958 atm

V = (0.09975 * 0.08206 * 295) / 0.958

V = 2.52 L

There is 2.52 L of O2 collected

7 0
2 years ago
100 points!! Brainliest if correct!!
snow_tiger [21]
Answer A: CO2

Reason: carbon dioxides formula is CO and the number next to it is the molecules
6 0
2 years ago
Read 2 more answers
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