Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
<u>Calculate the Total sludge production rate </u>
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
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Answer: 1.137*10^7 Btu/h.
Explanation:
Given data:
Efficiency of the plant = 4.5percent
Net power output of the plant = 150kw
Solution:
The required collection rate
QH = W/n
= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.
= 3333.333 *3412.152Btu/h.
= 11373840 Btu/h
= 1.137*10^7 Btu/h.
And air-conditioning system is to be filled for my ridge the containerBut that internally contains 5 kgDetermine the final quality of the arm 134
Answer:
203.0160
Explanation:
Because you add then subtract then multiply buy 7 the subtract then divide then you add that to the other numbers you got than boom