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Olin [163]
3 years ago
11

12. A structural component is fabricated from an alloy that has a plane strain fracture toughness of It has been determined that

this component fails at a stress of 300 MPa when the maximum length of a surface crack is 0.95 mm. What is the maximum allowable surface crack length (in mm) without fracture for this same component exposed to a stress of 300 MPa and made from another alloy with a plane-strain fracture toughness of 35 MPa m (31.9 ksi in. ). 40 MPa m (36.4 ksi in. ). 45 MPa m. 57.5 MPa m

Engineering
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

Q1 = 4.233 mm

Explanation:

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The objective of a properly proportioned concrete mix are: a.__________________________________________________________ b.______
sukhopar [10]

Answer:

The objective of a properly proportioned concrete mix are:

  • To produce the combination of cementitious material, water, and aggregate that meets the requirements of a particular structure, portion of a structure, or series of structures at least cost.
  • To produce concrete of the specified properties.
  • To produce a satisfactory of end product, such as beam, column or slab as economically as possible.

Cheers!

4 0
3 years ago
Read 2 more answers
If the atomic radius of copper is 0.128 nm, calculate the volume of its unit cell in cubic meters.
Alex_Xolod [135]

Answer:

Volume of face centered cubic cell=4.74531*10^{-29} m^3

Explanation:

Consider the face centered cubic cell:

1 atom at each corner of cube.

1 atom at center of each face.

Consider the one face (ABCD) as shown in attachment for calculation:

Length of the all sides of face centered cubic cell is L.

Volume of face centered cubic cell= L^3

Now Consider the figure shown in attachment:

According to Pythagoras theorem on ΔADC.

L^{2}+L^2=(4a)^2     (a is the atomic radius)

L=\frac{4a}{\sqrt{2}} (Put in the formula of Volume)

Volume of face centered cubic cell= L^3

Volume of face centered cubic cell= (\frac{4a}{\sqrt{2}})^3

Volume of face centered cubic cell= (\frac{4(0.128*10^{-9}}{\sqrt{2}})^3

Volume of face centered cubic cell=4.74531*10^{-29} m^3

3 0
4 years ago
The reading on a mercury manometer at 70(°F) (open to the atmosphere at one end) is 25. 62(in). The local acceleration of gravit
Ilya [14]

The absolute pressure in psia being measured is; 27.228 psia

<h3>What is the absolute Pressure?</h3>

Formula for absolute Pressure is;

Absolute pressure = Atmospheric pressure + Gauge pressure

P_{abs} = P_{atm} + P_g

We are given;

P_atm = 29.86 (in Hg) = 14.666 psia

Density of mercury at 70 °F; ρ = 13.543 g/cm³

Mercury Manometer reading; h = 25.62 in

Acceleration due to gravity; g = 32.243 ft/s²

Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243

When we multiply and covert to psia gives; P_g = 12.562 psia

Thus;

P_abs = 14.666 + 12.562

P_abs = 27.228 psia

Read more about Absolute Pressure at; brainly.com/question/17200230

7 0
2 years ago
Ben leads a team of a few engineers at a robotics firm. A couple of them would like to improve their skills by taking additional
Anit [1.1K]

Answer:

i dont know

Explanation:

4 0
3 years ago
The thrust F of a screw propeller is known to depend upon the diameter d,speed of advance \nu ,fluid density p, revolution per s
musickatia [10]

Answer:

<em>screw thrust = ML</em>T^{-2}<em> </em>

Explanation:

thrust of a screw propeller is given by the equation = pV^{2}D^{2} x \frac{ND}{V}Re

where,

D is diameter

V is the fluid velocity

p is the fluid density

N is the angular speed of the screw in revolution per second

Re is the Reynolds number which is equal to  puD/μ

where p is the fluid density

u is the fluid velocity, and

μ is the fluid viscosity = kg/m.s = ML^{-1}T^{-1}

<em>Reynolds number is dimensionless so it cancels out</em>

The dimensions of the variables are shown below in MLT

diameter is m = L

speed is in m/s = LT^{-1}

fluid density is in kg/m^{3} = ML^{-3}

N is in rad/s = LL^{-1}T^{-1} =

If we substitute these dimensions in their respective places in the equation, we get

thrust = ML^{-3}(LT^{-1}) ^{2}L^{2}\frac{T^{-1} L}{LT^{-1} }

= ML^{-3}L^{2}T^{-2}

<em>screw thrust = ML</em>T^{-2}<em> </em>

This is the dimension for a force which indicates that thrust is a type of force

6 0
3 years ago
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