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Anettt [7]
3 years ago
5

How many moles of helium are 8.84×1024 atoms of He?

Chemistry
1 answer:
insens350 [35]3 years ago
4 0

Answer:

14.68 moles of He

Explanation:

To do this, just remember Avogadro's Constant or Avogadro's number. This constant tells us how many units ( in this case atoms) there are in a mole of ANY type of substance.

Avogadro's constant is 6.022140857 × 10²³ units per mole.

Now that we know how many atoms there are in 1 mole, we can use this as our conversion factor.

8.84 x 10²⁴ atoms of He →  moles of He

8.84\times10^{24} atoms of He\times\dfrac{1moleofHe}{6.022140857\times10^{23}atomsofHe}=14.68molesofHe

So the answer would be:

14.68 moles of He

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"You measure 48.9 mL of a solution of sulfuric acid with an unknown concentration, and carefully titrate this solution using a 1
Blizzard [7]

Answer:

C= 0.532M

Explanation:

The equation of reaction is

H2SO4 + 2KOH = K2SO4+ H2O

nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml

Applying

CAVA/CBVB = nA/nB

(CA× 48.9)/(1.5×34.7)= 1/2

Simplify

CA= 0.532M

6 0
3 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o
jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H)  = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

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6 0
2 years ago
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D is the correct answer... if u need in depth let me know
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jelani and Mikah are watching an approaching storm from their living room window. All of a sudden they see a bright flash of lig
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