Answer:
Purplemath
The first term in the binomial is "x2", the second term in "3", and the power n is 6, so, counting ... x12 + 18x10 + 135x8 + 540x6 + 1215x4 + 1458x2 + 729 ... So memorize the Theorem and get the easy points.
Answer:
The ramp lands at an horizontal distance of 3.989 m
Explanation:
Range: Range is defined as the horizontal distance of a projectile from the point of projection to the point where the projectile hits the projection plane again. It is measure in meters (m)
R = U²sin2∅/g..................................... Equation 1
Where R = The horizontal distance from the end of the ramp, U = rider's speed, ∅ = the ramp's angle to the horizontal.
<em>Given: U = 6.3 m/s, ∅ = 40°, g = 9.8 m/s²</em>
<em>Substituting these values into equation 1</em>
<em>R = [6.3²sin2(40)]/9.8</em>
<em>R = (39.69×sin80)/9.8</em>
<em>R = 39.69×0.985/9.8</em>
R = 3.989 m
Thus the ramp lands at an horizontal distance of 3.989 m
-9.8 m/s^s because thats the earth gravity so it will lose 9.8 m/s^2 until its stop and thats because its the opposite of the force towards the earth!
Hope it helps
Answer:
I₃/Io % = 0.8.59
Explanation:
A polarizer is a complaint sheet for light in the polarization direction and blocks the perpendicular one. When we use two polarizers the transmission between them is described by Malus's law
I = I₀ cos² θ
Let's apply the previous exposures in our case, the light is indicatively not polarized, so the first polarized lets half of the light pass
I₁ = ½ I₀
The light transmitted by the second polarizer
I₂ = I₁ cos² θ
I₂ = (½ I₀) cos2 28
The transmission by the polarizing third is
I₃ = I₂ cos² θ₃
The angle of the third polarizer with respect to the second is
θ₃ = 90-28
θ₃ = 62º
I₃ = (½ I₀ cos² 28 cos² 62)
Let's calculate
I₃ = Io ½ 0.7796 0.2204
I₃ = Io 0.0859
I₃/Io= 0.0859 100
I₃/Io % = 0.8.59
